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3 years ago

15

What is the pH of a solution that has a hydronium ion concentration 100 times greater than a solution with a pH of 4?

1 answer:

Marta_Voda [28]3 years ago

5 0

The answer is (2) 2. First of all, a greater hydronium ion concentration means more acidic, so we need a lower pH. Also, you need to remember that pH is on a base 10 log scale. This means that a difference by a factor of 10 in concentration is a difference of 1 on the pH scale. So since the difference is a factor of 100 (10^2), the difference is 2. We already established that the pH must be lower, so your answer is 4 - 2 = 2.

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postnew [5]

There are 48.72 g Fluorine ions

<h3>Further explanation </h3>

Proust stated the Comparative Law that compounds are formed from elements with the same Mass Comparison so that the compound has a fixed composition of elements

In the same compound, although from different sources and formed by different processes, it will still have the same composition/comparison

%F in CaF₂ :

$\tt \%F=\dfrac{2.Ar~F}{MW~CaF_2}\times 100\%\\\\\%F=\dfrac{2.19}{78}\times 100\5=48.72\%$

mass of Fluorine :

$\tt 48.72\%\times 200=97.44~g$

So mass Fluorine ions(2 ions F in CaF₂⇒Ca²⁺+2F⁻) :

$\tt =\dfrac{97.44}{2}=48.72~g$

7 0

3 years ago

A balloon is filled to a volume of 1.6 L at 278 K. The balloon is left outside overnight and the temperature has dropped to 253

german

Explanation:

Charles' law gives the relationship between the volume and the temperature of the gas. Mathematically,

Volume ∝ Temperature

i.e. $\dfrac{V_1}{V_2}=\dfrac{T_1}{T_2}$

We have, V₁ = 1.6 L, T₁ = 278 K, T₂ = 253, V₂=?

$V_2=\dfrac{V_1T_2}{T_1}\\\\V_2=\dfrac{1.6\times 253}{278}\\\\V_2=1.45\ L$

So, the new volume is 1.45 L.

6 0

3 years ago

Calculate the molarity of a solution that contains 3.00 grams Na2SO4 in 25 mL of solution.

Naddik [55]

Answer:

M Na2SO4 sln = 0.8448 M

Explanation:

molarity (M) [=] mol/L

∴ mass Na2SO4 = 3.00 g

∴ volume soln = 25 mL = 0.025 L

∴ molar mass Na2SO4 = 142.04 g/mol

⇒ mol Na2SO4 = (3.00 g)*(mol/142.04 g) = 0.02112 mol

⇒ M Na2SO4 sln = (0.02112 mol/0.025 L ) = 0.8448 M

3 0

4 years ago

IM JUST GIVING AWAY POINTS!!!!!!

myrzilka [38]

2.5128e10 is the answer

6 0

3 years ago

Read 2 more answers

PLEASE ANSWER QUICKLY I'M IN A TEST

Natasha_Volkova [10]

D is the correct answer......

hope it help, please thank me if it did.....

4 0

3 years ago

Read 2 more answers