Answer:
C- both!
Explanation:
In a chemical reaction, the total mass and total charge has to be balanced on both sides of the "equation", therefore both are conserved
Answer:
The average atomic mass is 86.565
Explanation:
An element's average atomic mass is the sum of the products of the masses of the isotopes of the element and their percentage abundance divided by 100
The average atomic mass of the Element X is given as follows;
Isotope type 1 (85.91) ×
Isotope Abundance (%) Mass /100 Portion of average mass
Type 1 67.25 × 85.91 ÷ 100 57.774475
Type 2 32.75 × 87.91 ÷ 100 28.790525
Average atomic mass = 86.565
The average atomic mass = 86.565.
<h2>Bombarded α-Particles on a thin Sheet of Gold
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Explanation:
- Rutherford Atomic Model is also known as " The plum pudding model"
- Rutherford’s in his experiment bombarded α-particles which are of high energy on a thin sheet of gold nearly 100 nm of thickness and observed the trajectory path of these particles after interacting with the foil of gold.
- He placed a fluorescent screen of zinc sulfide around the thin gold foil to study the trajectory path of the α-particles and its deflection.
- Most of the α-particles passed through the gold foil were not deflected as most of the internal space of the atom was empty.
- The result was that the positive charge of the atom occupies very little space.
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Answer:
Mass = 33.515 g
Explanation:
Given data:
Volume of ammonia = 45.0 L
Temperature = 57.0°C (57 +273 = 330 K)
Pressure = 900 mmHg
Mass of ammonia = ?
Solution:
Formula:
PV = nRT
We will use R = 62.364 (L * mmHg)/(mol * K) because pressure is given in mmHg.
900 mmHg × 45.0 L = n × 62.364L * mmHg/mol * K × 330 K
40500 mmHg.L = n × 20580.12L * mmHg/mol
n= 40500 mmHg.L/ 20580.12L * mmHg/mol
n = 1.9679 mol
Mass of ammonia:
Mass = number of moles × molar mass
Mass = 1.9679 mol × 17.031 g/mol
Mass = 33.515 g
When we multiply or divide the values the number of significant figures must be equal to the less number of significant figures in given value.