Answer:
-24 m/s
Explanation:
mass of the bowling ball = 3 kg
time (t) = 0.3 seconds
Force = 24 N
initial velocity u = ???
We know that;
Force = mass × acceleration (a)
So;
24 = 3 × a
a = 24/3
a = 8 m/s²
Also;
From equation of motion; acceleration is given by the relation;
if v = 0
then ;
24 = 0- u
u = -24 m/s
Thus; the initial velocity of the bowling ball when it first touched the mattress = -24 m/s
The given question is incomplete. The complete question is as follows.
A box of oranges which weighs 83 N is being pushed across a horizontal floor. As it moves, it is slowing at a constant rate of 0.90 m/s each second. The push force has a horizontal component of 20 N and a vertical component of 25 N downward. Calculate the coefficient of kinetic friction between the box and the floor.
Explanation:
The given data is as follows.
= 20 N,
= 25 N, a = -0.9
W = 83 N
m =
= 8.46
Now, we will balance the forces along the y-component as follows.
N = W +
= 83 + 25 = 108 N
Now, balancing the forces along the x component as follows.
= ma
= 7.614 N
Also, we know that relation between force and coefficient of friction is as follows.
=
= 0.0705
Thus, we can conclude that the coefficient of kinetic friction between the box and the floor is 0.0705.