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Advocard [28]
3 years ago
13

Why is sugar soluble in water while oil cannot form a solution?​

Chemistry
2 answers:
Katyanochek1 [597]3 years ago
7 0

Answer:

Oil is a hydrophobic substance, therefore cannot interact with water. Sugar is hydrophilic, water loving, and has the ability to dissolve in water.

Explanation:

Viefleur [7K]3 years ago
4 0

Answer:

the water and alcohol interact, which means the water doesn't even dissolve the sugar or color as well as it normally would. Oil molecules are not polar so they cannot dissolve either the coloring or the sugar.

Explanation:

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What’s the answer to this? Pls help
Sedaia [141]

Answer:

First choice

Explanation:

7 0
2 years ago
PLEASE HELP! I DONT KNOW WHAT TO DO! ITS ALOT PLEASE HELP THO!
kirza4 [7]

Answer:

CuCl2 (aq) + (NH4)2CO3(aq) → NH4Cl(aq) + CuCO3(s)

* CuCl2 (aq) + (NH4)2CO3(aq) → 2NH4Cl(aq) + CuCO3(s)

*Cu(2+)(aq)+ 2Cl(-)(aq) + 2NH4(+)(aq) + CO3(2-)(aq) →2NH4(+)(aq) + Cl(-)(aq) + CuCO3(s)

*Cu(2+)(aq)+ CO3(2-)(aq) → CuCO3(s)

*2HCl(aq) + 2MgCO3(s) → 2MgCl(aq) + H2O(l) + 2CO2(g)

* 2H(+)(aq) + 2Cl(-)(aq) + 2MgCO3(s) → 2Mg(2+)(aq) +2Cl(-) (aq) + H2O(l) + 2CO2(g)

* 2MgCO3(s) → 2Mg(2+)(aq) + H2O(l) + 2CO2(g)

*ZnCl2(aq) + 2AgC2H3O2(aq) → 2AgCl(s) + Zn(C2H3O2)2(aq)

*Zn(2+)(aq) + 2Cl(-)(aq) + 2Ag(+)(aq) + C2H3O2(-)(aq) → 2AgCl(s) + Zn(2+)(aq) 2C2H3O2(-)(aq)

*2Cl(-)(aq) + 2Ag(+)(aq)  → 2AgCl(s)

*MnO(s) + H2SO4(aq) → MnSO4(s) + H2O (l)

*MnO(s) + 2H(+)(aq) + SO4(2-)(aq) → MnSO4(s) + H2O (l)

*MnO(s) + 2H(+)(aq) + SO4(2-)(aq) → MnSO4(s) + H2O (l)

*FeS(s) + 2HCl (aq) → FeCl2(aq) + H2S(g)

*FeS(s) + 2H(+)(aq) + 2Cl(-)(aq)  → Fe(2+)(aq)+ 2Cl(-)(aq)) + H2S(g)

*FeS(s) + 2H(+)(aq)  → Fe(2+)(aq)+ H2S(g)

Explanation:

In the first equation you only need to know the rules of solubility. All chlorides are solubles  except Ag+ Pb+2 and Hg2(2+) and most carbonates are insolubles

<em>For ionic equations</em> Start with a balanced molecular equation.  Break all soluble strong electrolytes (compounds with (aq) beside them) into their ions  indicate the correct formula and charge of each ion . Indicate the correct number of each ion  and write (aq) after each ion . Bring down all compounds with (s), (l), or (g) unchanged.

<em>For net ionic equations </em>Write the balanced molecular equation.  Write the balanced complete ionic equation.  Cross out the spectator ions that are present.  Write the "leftovers" as the net ionic equation.

Before this, te equation must be balanced.

* CuCl2 (aq) + (NH4)2CO3(aq) → 2NH4Cl(aq) + CuCO3(s)

*Cu(2+)(aq)+ 2Cl(-)(aq) + 2NH4(+)(aq) + CO3(2-)(aq) →2NH4(+)(aq) + Cl(-)(aq) + CuCO3(s)

*Cu(2+)(aq)+ CO3(2-)(aq) → CuCO3(s)

*2HCl(aq) + 2MgCO3(s) → 2MgCl(aq) + H2O(l) + 2CO2(g)

* 2H(+)(aq) + 2Cl(-)(aq) + 2MgCO3(s) → 2Mg(2+)(aq) +2Cl(-) (aq) + H2O(l) + 2CO2(g)

* 2MgCO3(s) → 2Mg(2+)(aq) + H2O(l) + 2CO2(g)

*ZnCl2(aq) + 2AgC2H3O2(aq) → 2AgCl(s) + Zn(C2H3O2)2(aq)

*Zn(2+)(aq) + 2Cl(-)(aq) + 2Ag(+)(aq) + C2H3O2(-)(aq) → 2AgCl(s) + Zn(2+)(aq) 2C2H3O2(-)(aq)

*2Cl(-)(aq) + 2Ag(+)(aq)  → 2AgCl(s)

*MnO(s) + H2SO4(aq) → MnSO4(s) + H2O (l)

*MnO(s) + 2H(+)(aq) + SO4(2-)(aq) → MnSO4(s) + H2O (l)

*MnO(s) + 2H(+)(aq) + SO4(2-)(aq) → MnSO4(s) + H2O (l)

*FeS(s) + 2HCl (aq) → FeCl2(aq) + H2S(g)

*FeS(s) + 2H(+)(aq) + 2Cl(-)(aq)  → Fe(2+)(aq)+ 2Cl(-)(aq)) + H2S(g)

*FeS(s) + 2H(+)(aq)  → Fe(2+)(aq)+ H2S(g)

7 0
3 years ago
18. The mass of a quantity of NiCl2 is 24.6 g. How many formula units are in the sample?
Charra [1.4K]

Answer is: A. 1.1 3 1023 NiCl2 formula units.

m(NiCl₂) = 24.6 g; mass of nickel(II) chloride.

M(NiCl₂) = 129.6 g/mol; molar mass of nickel(II) chloride.

n(NiCl₂) = m(NiCl₂) ÷ M(NiCl₂).

n(NiCl₂) = 24.6 g ÷ 129.6 g/mol.

n(NiCl₂) = 0.19 mol; amount of nickel(II) chloride.

Na = 6.022·10²³ 1/mol; Avogadro constant.

N(NiCl₂) = n(NiCl₂) · Na.

N(NiCl₂) = 0.19 mol · 6.022·10²³ 1/mol.

N(NiCl₂) = 1.13·10²³; number of formula units.

4 0
3 years ago
Read 2 more answers
What are the 5 principles of kinetic molecular theory?
leva [86]
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I got this from my notes from my chemistry class last semester

</span>
8 0
3 years ago
Why couldn't you substitute 3m H2SO4 for concentrated HNO3 when oxidizing copper?
schepotkina [342]

This question seems to be an essay question from experiment. Different solution of oxidizing agent will have different strength.  Sulfuric acid or H2SO4 is weaker oxidizing agent when compared to nitric acid (HNO3). In this case, if you subtitute the H2SO4 you wouldn't be able to get the same result for the experiment.



5 0
3 years ago
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