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Vesna [10]
3 years ago
10

A typical sheet of weighing paper is 3.5 inches by 4.1 inches and weighs 0.45 g. What is its absorber thickness in g/cm^{2} 2 

?
Chemistry
1 answer:
SpyIntel [72]3 years ago
6 0

Answer:

\boxed{\textbf{0.0046 g/cm}^{2}}

Explanation:

1. Convert inches to centimetres

l= \text{4.1 in} \times \dfrac{\text{2.54 cm}}{\text{1 in}} = \text{10.2 cm}\\\\w= \text{3.5 in} \times \dfrac{\text{2.54 cm}}{\text{1 in}} = \text{8.89 cm}

2. Calculate the area

A = lw = 10.2 × 8.89= 90.3 cm²

3. Calculate the absorber thickness

\text{Absorber thickness} = \dfrac{\text{0.415 g}}{\text{90.3 cm}^{2}} = \textbf{0.0046 g/cm}^{2}\\\\\text{The absorber thickness is $\boxed{\textbf{0.0046 g/cm}^{2}}$}

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NADH and FADH 2 are important in cellular respiration because they deliver high-energy electrons to the electron transport syste
IceJOKER [234]

Answer:

Electron transport produces 3 ATP molecule(s) per NADH molecule and 2 ATP molecules(s) perFADH 2 molecule.

Explanation:

The mechanism by which ATP is produced is explained by the theory of chemosmotic coupling.

This theory establishes that the synthesis of ATP in cellular respiration comes from an electrochemical gradient existing between the internal membrane and the space of the intermembrane of the mitochondria, through the use of the energy of NADH and FADH2 that have been formed by the rupture of molecules rich in energy, such as glucose.

3 0
3 years ago
A 115.0-g sample of oxygen was produced by heating 400.0 g of potassium chlorate.2KClO3 Right arrow. 2KCI + 3O2What is the perce
STALIN [3.7K]

Answer:

73.4% is the percent yield

Explanation:

2KClO₃ →  2KCl  + 3O₂

This is a decomposition reaction, where 2 moles of potassium chlorate decompose to 2 moles of potassium chloride and 3 moles of oxygen.

We determine the moles of salt: 400 g . 1. mol /122.5g= 3.26 moles of KClO₃

In the theoretical yield of the reaction we say:

2 moles of potassium chlorate can produce 3 moles of oxygen

Therefore, 3.26 moles of salt, may produce (3.26 . 3) /2 = 4.89 moles of O₂

The mass of produced oxygen is: 4.89 mol . 32 g /1mol = 156.6g

But, we have produced 115 g. Let's determine the percent yield of reaction

Percent yield = (Produced yield/Theoretical yield) . 100

(115g / 156.6g) . 100 = 73.4 %

5 0
3 years ago
Which of the following is equal to 2.0 liters? 200 mL 2,000 cm3 20 m3 20,000 mm3
ololo11 [35]
It equals 2000  but in this case it would be 20,000mm3
4 0
4 years ago
A chemist must prepare of hydrochloric acid solution with a pH of at . He will do this in three steps: Fill a volumetric flask a
Eva8 [605]

Answer:

1.7 mL

Explanation:

<em>A chemist must prepare 550.0 mL of hydrochloric acid solution with a pH of 1.60 at 25 °C. He will do this in three steps: Fill a 550.0 mL volumetric flask about halfway with distilled water. Measure out a small volume of concentrated (8.0 M) stock hydrochloric acid solution and add it to the flask. Fill the flask to the mark with distilled water. Calculate the volume of concentrated hydrochloric acid that the chemist must measure out in the second step. Round your answer to 2 significant digits.</em>

Step 1: Calculate [H⁺] in the dilute solution

We will use the following expresion.

pH = -log [H⁺]

[H⁺] = antilog - pH = antilog -1.60 = 0.0251 M

Since HCl is a strong monoprotic acid, the concentration of HCl in the dilute solution is 0.0251 M.

Step 2: Calculate the volume of the concentrated HCl solution

We want to prepare 550.0 mL of a 0.0251 M HCl solution. We can calculate the volume of the 8.0 M solution using the dilution rule.

C₁ × V₁ = C₂ × V₂

V₁ = C₂ × V₂/C₁

V₁ = 0.0251 M × 550.0 mL/8.0 M = 1.7 mL

3 0
3 years ago
What are advantages of using uranium as an energy source
MariettaO [177]
Question:
What are advantages of using Uranium as an energy source?

Answer(s):
-Small amounts of Uranium generate large amounts of energy
-Uranium occurs in huge reserves
-It has a longer lifetime than other non-renewable sources of energy


-Brainly Answerer
4 0
4 years ago
Read 2 more answers
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