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Vesna [10]
4 years ago
10

A typical sheet of weighing paper is 3.5 inches by 4.1 inches and weighs 0.45 g. What is its absorber thickness in g/cm^{2} 2 

?
Chemistry
1 answer:
SpyIntel [72]4 years ago
6 0

Answer:

\boxed{\textbf{0.0046 g/cm}^{2}}

Explanation:

1. Convert inches to centimetres

l= \text{4.1 in} \times \dfrac{\text{2.54 cm}}{\text{1 in}} = \text{10.2 cm}\\\\w= \text{3.5 in} \times \dfrac{\text{2.54 cm}}{\text{1 in}} = \text{8.89 cm}

2. Calculate the area

A = lw = 10.2 × 8.89= 90.3 cm²

3. Calculate the absorber thickness

\text{Absorber thickness} = \dfrac{\text{0.415 g}}{\text{90.3 cm}^{2}} = \textbf{0.0046 g/cm}^{2}\\\\\text{The absorber thickness is $\boxed{\textbf{0.0046 g/cm}^{2}}$}

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A gallon of water has a mass of 3.79 kg. how many moles of water (18.02 g/mol) is this?
garik1379 [7]
First, we will convert the mass of the gallon to grams:
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Substitute natural gas (SNG) is a gaseous mixture containing CH4(g) that can be used as a fuel. One reaction for the production
Lynna [10]

Answer:

ΔH° of the reaction is -747.54kJ

Explanation:

Based on gas law, it is possible to find the ΔH of a reaction using ΔH of half reactions.

Using the reactions:

<em>(1) </em>C(graphite) + 1/2O₂(g) → CO(g) ΔH° = -110.5 kJ

<em>(2) </em>CO(g) + 1/2O₂(g) → CO₂(g) ΔH° = -283.0 kJ

<em>(3) </em>H₂(g) + 1/2O₂(g) → H₂O(l) ΔH° = -285.8 kJ

<em>(4) </em>C(graphite) + 2H₂(g) → CH₄(g) ΔH° = -74.81 kJ

<em>(5) </em>CH₄(g) + 2O₂(g) → CO₂(g) + 2H₂O(l) ΔH° = -890.3 kJ

The sum of 4×(4) + (5) gives:

4C(graphite) + 8H₂(g) + 2O₂(g) → CO₂(g) + 2H₂O(l) + 3CH₄(g)

ΔH° = -74.81 kJ ×4 - 890.3 kJ = -1189.54kJ

Now, this reaction - 4×(1) gives:

4CO(g) + 8H₂(g) → CO₂(g) + 2H₂O(l) + 3CH₄(g)

ΔH° = -1189.54kJ - 4×-110.5 = <em>-747.54kJ</em>

<em></em>

Thus <em>ΔH° of the reaction is -747.54kJ</em>

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