Answer:
the required electrical power when the room air and surroundings are at 30°C.= 52.51822 Watt
Explanation:
Power required to maintain the surface temperature at 150°C from 20°C
P= εσA(T^4-t^4)
P= power in watt
ε= emissivity
A= area of surface
T= 150°C= 423 K
t= 20°C= 303K
/sigma= 5.67×10^{-8} watt/m^2K^4
putting vales we get
P=52.51822 Watt
the required electrical power when the room air and surroundings are at 30°C.= 52.51822 Watt
Answer:
The electrical potential energy is 0.027 Joules.
Explanation:
The values from the question are
charge (q) =
Electric Field strength (E) =
Distance from source (d) = 0.030 m
Now the formula for the electrical potential energy (U) is given by
So now insert the values to find the answer
On further solving
a) Density of the liquid:
b) Weight of the liquid: 1372 N
Explanation:
Translation of the text:
<em>"A full tank with liquid weighs 175kg. Which is 5 times the mass of the empty vessel. Knowing that the inside volume of the vessel is 0.17kl, calculate: </em>
<em>a) the density of the liquid; </em>
<em>b) the weight of the liquid."</em>
a)
We know that the full tank with liquid has a total mass of M = 175 kg. We can write the total mass as
(1)
where
is the mass of the liquid
is the mass of the vessel
We also know that the total mass M is 5 times the mass of the empty vessel, so we have:
which is the mass of the empty vessel.
Therefore, we can find the mass of the liquid only using (1):
The density of the liquid is given by
where
m = 140 kg (mass of the liquid)
V = 0.170 kL = 170 L = (volume of the liquid, which is equal to the volume of the vessel)
So we get
b)
The weight of a body is given by
where
m is its mass
g is the acceleration due to gravity
For the liquid in this problem, we have
m = 140 kg (mass)
(acceleration due to gravity)
Therefore, its weight is
Learn more about density:
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