The people of Finland, who are secluded to some degree from the rest of the world by water, develop certain diseases due to the lack of genetic material from other ethnicities and races.
Physical barriers prevent fish from one stream from mating with fish from another stream, leading to a less varied gene pool among those fish. As time passes, the fish become unable to successfully mate with other groups.
A mountain range prevents two types of goat from mating, causing the gene pool to become less varied.<span>
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Answer : The mole fraction of NaCl in a mixture is, 0.360
Explanation : Given,
Moles of
= 7.21 mole
Moles of
= 9.37 mole
Moles of
= 3.42 mole
Now we have to calculate the mole fraction of
.
![\text{Mole fraction of }NaCl=\frac{\text{Moles of }NaCl}{\text{Moles of }NaCl+\text{Moles of }KCl+\text{Moles of }LiCl}](https://tex.z-dn.net/?f=%5Ctext%7BMole%20fraction%20of%20%7DNaCl%3D%5Cfrac%7B%5Ctext%7BMoles%20of%20%7DNaCl%7D%7B%5Ctext%7BMoles%20of%20%7DNaCl%2B%5Ctext%7BMoles%20of%20%7DKCl%2B%5Ctext%7BMoles%20of%20%7DLiCl%7D)
Now put all the given values in this formula, we get:
![\text{Mole fraction of }NaCl=\frac{7.21}{7.21+9.37+3.42}=0.360](https://tex.z-dn.net/?f=%5Ctext%7BMole%20fraction%20of%20%7DNaCl%3D%5Cfrac%7B7.21%7D%7B7.21%2B9.37%2B3.42%7D%3D0.360)
Therefore, the mole fraction of NaCl in a mixture is, 0.360
Foods are a solid we need to survive
<u>Answer:</u> The equilibrium concentration of water is 0.597 M
<u>Explanation:</u>
Equilibrium constant in terms of concentration is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as ![K_{c}](https://tex.z-dn.net/?f=K_%7Bc%7D)
For a general chemical reaction:
![aA+bB\rightleftharpoons cC+dD](https://tex.z-dn.net/?f=aA%2BbB%5Crightleftharpoons%20cC%2BdD)
The expression for
is written as:
![K_{c}=\frac{[C]^c[D]^d}{[A]^a[B]^b}](https://tex.z-dn.net/?f=K_%7Bc%7D%3D%5Cfrac%7B%5BC%5D%5Ec%5BD%5D%5Ed%7D%7B%5BA%5D%5Ea%5BB%5D%5Eb%7D)
The concentration of pure solids and pure liquids are taken as 1 in the expression.
For the given chemical reaction:
![2H_2S(g)+O_2(g)\rightleftharpoons 2S(s)+2H_2O(g)](https://tex.z-dn.net/?f=2H_2S%28g%29%2BO_2%28g%29%5Crightleftharpoons%202S%28s%29%2B2H_2O%28g%29)
The expression of
for above equation is:
![K_c=\frac{[H_2O]^2}{[H_2S]^2\times [O_2]}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BH_2O%5D%5E2%7D%7B%5BH_2S%5D%5E2%5Ctimes%20%5BO_2%5D%7D)
We are given:
![[H_2S]_{eq}=0.671M](https://tex.z-dn.net/?f=%5BH_2S%5D_%7Beq%7D%3D0.671M)
![[O_2]_{eq}=0.587M](https://tex.z-dn.net/?f=%5BO_2%5D_%7Beq%7D%3D0.587M)
![K_c=1.35](https://tex.z-dn.net/?f=K_c%3D1.35)
Putting values in above expression, we get:
![1.35=\frac{[H_2O]^2}{(0.671)^2\times 0.587}](https://tex.z-dn.net/?f=1.35%3D%5Cfrac%7B%5BH_2O%5D%5E2%7D%7B%280.671%29%5E2%5Ctimes%200.587%7D)
![[H_2O]=\sqrt{(1.35\times 0.671\times 0.671\times 0.587)}=0.597M](https://tex.z-dn.net/?f=%5BH_2O%5D%3D%5Csqrt%7B%281.35%5Ctimes%200.671%5Ctimes%200.671%5Ctimes%200.587%29%7D%3D0.597M)
Hence, the equilibrium concentration of water is 0.597 M
Correct answer There are 68 grams are in atoms