1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
geniusboy [140]
2 years ago
11

Who was the 37 persident

Chemistry
2 answers:
sammy [17]2 years ago
3 0

Answer:

Richard Nixon was elected the 37th President of the United States (1969-1974) after previously serving as a U.S. Representative and a U.S. Senator from California.

Explanation:

const2013 [10]2 years ago
3 0

Answer:

Explanation:

Richard Nixon was elected the 37th President of the United States (1969-1974) after previously serving as a U.S. Representative and a U.S. Senator from California.

You might be interested in
Number 14 please help.. chemistry
Zolol [24]

Taking into account the definition of density, the mass of a substance with a volume of 150 cm³ and a density of 1.5 \frac{g}{cm^{3} }  is 225 grams.

<h3>What is density</h3>

Density is defined as the property that matter, whether solid, liquid or gas, has to compress into a given space.

In other words, density is a quantity that allows us to measure the amount of mass in a certain volume of a substance.

Then, the expression for the calculation of density is the quotient between the mass of a body and the volume it occupies:

density=\frac{mass}{volume}

From this expression it can be deduced that density is inversely proportional to volume: the smaller the volume occupied by a given mass, the higher the density.

<h3>Mass of the substance in this case</h3>

In this case, you know that:

  • Density= 1.5 \frac{g}{cm^{3} }
  • Volume= 150 cm³

Replacing in the definition of density:

1.5 \frac{g}{cm^{3} } =\frac{mass}{150 cm^{3} }

Solving:

mass= 1.5 \frac{g}{cm^{3} }  ×150 cm³

<u><em>mass= 225 g</em></u>

In summary, the mass of a substance with a volume of 150 cm³ and a density of 1.5 \frac{g}{cm^{3} }  is 225 grams.

Learn more about density:

brainly.com/question/952755

brainly.com/question/1462554

#SPJ1

7 0
2 years ago
2. The term for a reaction where two solutions are mixed and an insoluble substance forms is called a _____ reaction.
Norma-Jean [14]

Answer:

precipitation reaction.

Explanation:

an insoluble substance is called a precipitate, so the reaction is a precipitation reaction.

8 0
3 years ago
Please help me!!!!!!!!
ValentinkaMS [17]
It is surface runoff
6 0
3 years ago
What allows electricity to be conducted when dissolved in water
laila [671]
When salt is in water it creates electrolytes which are able to conduct electricity
7 0
3 years ago
The molecular weight of water, H2O, is 18.02 g over mol. How many moles of water are in 24.3 g of water? Express the answer usin
Zolol [24]

Answer:

1.35

Explanation Use the mole formla and multiply and them apply the sig fig rules and you will get the moles of water hope this helps god bless

4 0
3 years ago
Other questions:
  • Which formula represents an ionic compound AICI3
    12·1 answer
  • Criteria for evaluating alternative solutions includes all of the following except :
    5·1 answer
  • 1s22s22p63523p645230104p5<br> Which element is this?<br> answer : bromine
    15·1 answer
  • Which of these provides the BEST evidence that the distribution of Earth’s oceans has changed over time?
    12·1 answer
  • What is the density of an unknown object with a mass of 225g and a volume of 500cm3
    6·1 answer
  • What is the internal energy u of one mole of air on a very hot summer day (35∘c)? express your answer numerically in joules to t
    9·1 answer
  • Zn(s)+2HCl(aq)-&gt;ZnCl2(aq)+H2(g)
    5·2 answers
  • Which iconic compound is used as a building material?
    12·1 answer
  • PLEASE PLEASE HELP!!!!
    11·1 answer
  • It is found that up to 0.0110 g of SrF2 dissolves in 100 ml of aqueous solution at a certain temperature. Determine the value of
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!