Magnesium hydroxide react with hydrochloride to give magnesium chloride and water
THe word equation
magnesium hydroxide +hydrochroric acid---> Magnesium chloride+water
chemical equation
Mg(OH)2(S) + 2HCl (L)--> Mgcl2(S) + 2H2O(l)
when balancing the equation we count the number of molecules in the reactant side which should balance with molecules in the product side.
I think it will be D or B but my mine answer is D
Answer:
13.1 L
Explanation:
Using the combined gas law:
P1V1/T1 = P2V2/T2
Where;
P1 = initial pressure (atm)
P2 = final pressure (atm)
V1 = initial volume (L)
V2 = final volume (L)
T1 = initial temperature (K)
T2 = final temperature (K)
Based on the information provided in this question;
P1 = 1.95 atm
P2 = 0.65 atm
V1 = 5.0 L
V2 = ?
T1 = 20 °C = 20 + 273 = 293K
T2 = -15 °C = -15 + 273 = 258K
Using P1V1/T1 = P2V2/T2
1.95 × 5/293 = 0.65 × V2/258
9.75/293 = 0.65V2/258
0.0333 = 0.00252V2
V2 = 0.0333 ÷ 0.00252
V2 = 13.1 L
Answer:
Explanation:
The whole sample is 269
%copper = 127/269 * 100 = 47.2%
%chlorine = 142/269 * 100 = 52.8%
That's all you are asking. Is there more?
Answer:the first column has one valance electron the second has 2 and so on.
The only exception is helium that has 2.
Explanation:
