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3 years ago

Combine each side and then balance the whole equation. Al+HCl=AlCl3+H^+

Chemistry

1 answer:

Aneli [31]3 years ago

5 0

Answer:

$2Al + 6 HCl ---> 2AlCl_3 + 3 H_2$

Explanation:

The valency of aluminium is +3 while the valency of chlorine is -1

we will first write the half reactions

Half oxidation reaction

$Al -----> Al^{3+} + 3^{e-}\\2H^+ 2e^- ----> H_2\\Cl + e^- -----> Cl^-$

Now will write the complete equation-

$Al + HCl -----> AlCl_3 + H_2$

The balanced equation would be

$2Al + 6 HCl ---> 2AlCl_3 + 3 H_2$

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3 years ago

A 0.4647-g sample of a compound known to contain only carbon, hydrogen, and oxygen was burned in oxygen to yield 0.01962 mol of

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Answer:

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Explanation:

The given values are:

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Moles of water,

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Let the compound's formula will be:

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Combustion's general equation will be:

⇒ $C_{x}H_{y}O_{z}+x+(\frac{y}{4}-\frac{z}{2}) O_{2}=xCO_{2}+\frac{y}{2H_{2}O}$

On putting the estimated values, we get

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x : y : z = $0.01962:0.03922:0.01187$

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= $3:6:2$

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