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Anika [276]
3 years ago
9

Combine each side and then balance the whole equation. Al+HCl=AlCl3+H^+

Chemistry
1 answer:
Aneli [31]3 years ago
5 0

Answer:

2Al + 6 HCl ---> 2AlCl_3 + 3 H_2

Explanation:

The valency of aluminium is +3 while the valency of chlorine is -1

we will first write the half reactions

Half oxidation reaction

Al -----> Al^{3+} + 3^{e-}\\2H^+ 2e^- ----> H_2\\Cl + e^- -----> Cl^-

Now will write the complete equation-

Al + HCl -----> AlCl_3 + H_2

The balanced equation would be

2Al + 6 HCl ---> 2AlCl_3 + 3 H_2

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A 0.1510 gram sample of a hydrocarbon produces 0.5008 gram CO2 and 0.1282 gram H2O in combustion analysis. Its
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In a combustion of a hydrocarbon compound, 2 reactions are happening per element:

C + O₂ → CO₂
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Thus, we can determine the amount of C and H from the masses of CO₂ and H₂O produced, respectively.

1.) Compute for the amount of C in the compound. The data you need to know are the following:
Molar mass of C = 12 g/mol
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Molar mass of H = 1 g/mol
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Divide the least number between the two to each of their individual amounts:
C = 0.01138/0.01138 = 1
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The ratio should be a whole number. So, you multiple 4 to each of the ratios:
C = 1*4 = 4
H = 1.25*4 = 5

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Molar mass = 4(12 g/mol) + 5(1 g/mol) = 53 g/mol
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106 g/mol / 53 g/mol = 2
Thus, you need to multiply 2 to the subscripts of the empirical formula.

Molecular Formula = C₈H₁₀

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