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Ket [755]
3 years ago
9

g suppose a spring with spring constant of 50 N/m is hanging from the ceiling. You hang 2.0 kg mass from the spring. How far is

the spring stretched
Physics
1 answer:
adelina 88 [10]3 years ago
8 0

Answer:

The extension of the spring is 0.392 m.

Explanation:

Given;

spring constant, k = 50 N/m

mass attached to the spring, m = 2.0 kg

let the extension of the spring = x

The extension of the spring is calculated by applying Hook's law;

F = kx

mg = kx

x = \frac{mg}{k} \\\\x = \frac{2 \times 9.8}{50} \\\\x = 0.392 \ m

Therefore, the extension of the spring is 0.392 m.

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Two objects 5 kg and 7 kg are attached to the end of inextensible string which passes over frictionless pulley
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Answer:

ans:

tenson(T) = 20 N

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Answer:

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Explanation:

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Two coherent sources of radio waves, A and B, are 5.00 meters apart. Each source emits waves with wavelength 6.00 meters. Consid
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Answer:

a

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b

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From the question we are told that

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=>    z =  (1 \ m ,  4 \ m )

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