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notsponge [240]
3 years ago
12

An unknown weak base with a concentration of 0.0910 M has a pH of 10.50. What is the Kb of this base

Chemistry
1 answer:
shusha [124]3 years ago
6 0

Answer: The K_b for the weak base is 3.5\times 10^{-3}

Explanation:

A^-+H_2O\rightarrow HA+OH^-

cM                   0          0

c-c\alpha           c\alpha       c\alpha 

So dissociation constant will be:

K_b=\frac{[HA][OH^-]}{[A^-]}

K_b=\frac{(c\alpha)^{2}}{c-c\alpha}

Given :

c= 0.0910 M and pH = 10.50

pOH = 14-pH = 14-10.50 = 3.5

Also pOH=-log[OH^-]

[OH^-]=antilog(-3.5)= 3.2\times 10^{-4}M

[OH^-]=c\alpha=3.2\times 10^{-4}

K_b=\frac{(3.2\times 10^{-4})^2}{(0.0910-3.2\times 10^{-4}}

K_b=\frac{(3.2\times 10^{-4})^2}{(0.09068}

K_b=3.5\times 10^{-3}

Thus K_b for the weak base is 3.5\times 10^{-3}

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ArbitrLikvidat [17]
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An exothermic reaction is a type of reaction in which the reaction system lose energy to the environment and thus, the energy content of the reactants is more than that of the product formed. Because of this, the enthapyl change of an exothermic reaction is always negative. 
An endothermic reaction is a type of reaction in which the reaction system absorb energy from the environment. Thus, the energy contents of the products is always higher than that of the reactants and the enthapyl change of the reaction is always positive. During the course of the reaction, the reaction container is usually cold to the touch because energy is been absorbed from the environment.
4 0
3 years ago
Determine the pH of the resulting solution if 25 mL of 0.400 M strychnine (C21H22N2O2) is added to 50 mL of 0.200 M HCl? Assume
DIA [1.3K]

Answer:

pH = 4.56

Explanation:

The strychnine reacts with HCl as follows:

C₂₁H₂₂N₂O₂ + HCl ⇄ C₂₁H₂₂N₂O₂H⁺ + Cl⁻

<em />

For strychnine buffer:

pOH = 5.74 + log [C₂₁H₂₂N₂O₂H⁺] / [C₂₁H₂₂N₂O₂]

Initial moles of C₂₁H₂₂N₂O₂ are:

0.025L * (0.400 mol / L) = 0.01 moles C₂₁H₂₂N₂O₂

And of HCl are:

0.05L * (0.200 mol / L) = 0.01 moles HCl

That means after the reaction, you will have just 0.01 moles of C₂₁H₂₂N₂O₂H⁺ in 50mL + 25mL = 0.075L. And molarity is:

[C₂₁H₂₂N₂O₂H⁺] = 0.01 mol / 0.075L = 0.1333M

This conjugate acid, is in equilibrium with water as follows:

C₂₁H₂₂N₂O₂H⁺(aq) + H₂O(l) ⇄ C₂₁H₂₂N₂O₂ + H₃O⁺

<em />

<em>Where Ka = Kw / Kb = 1x10⁻¹⁴ / 1.8x10⁻⁶ = 5.556x10⁻⁹</em>

<em />

Ka is defined as:

Ka = 5.556x10⁻⁹ = [C₂₁H₂₂N₂O₂] [H₃O⁺] / [C₂₁H₂₂N₂O₂H⁺]

In equilibrium, concentrations are:

C₂₁H₂₂N₂O₂ = X

H₃O⁺ = X

C₂₁H₂₂N₂O₂H⁺ = 0.1333M - X

Replacing in Ka expression:

5.556x10⁻⁹ = [X] [X] / [0.1333M - X]

7.39x10⁻¹⁰ - 5.556x10⁻⁹X = X²

7.39x10⁻¹⁰ - 5.556x10⁻⁹X - X² = 0

Solving for X:

X = - 2.72x10⁻⁵M → False solution. There is no negative concentrations

X = 2.72x10⁻⁵M → Right solution.

As H₃O⁺ = X

H₃O⁺ = 2.72x10⁻⁵M

And pH = -log H₃O⁺

<h3>pH = 4.56</h3>
4 0
3 years ago
What does the red represent on the model? *
kaheart [24]
The red is an oxygen molecule. 1 oxygen and 2 hydrogen =h2o or water!
6 0
3 years ago
Extra Stoichiometry Practice
Irina-Kira [14]

Answer: 50. 4g

Explanation:

First calculate number of moles of aluminium in 38.8g

Moles = 38.8g/ 26.982mol/g

= 1.44mol

By looking at the balance equation you can see that 4 moles of aluminium produce 2 moles of aluminium oxide.

4 = 2

1.4 = x

Find the value of x

x= (1.4×2)/4= 0.72 mol

0.72 moles of aluminium oxide are produced from 38.8g of aluminium

Now find the mass of aluminium produced.

Mass = moles × molar mass

= 0.72mol × 69.93 mol/g

= 50.4g

8 0
2 years ago
1)If I mixed salt in water I would expect the salt to:
zaharov [31]

Answer:

1)If I mixed salt in water I would expect the salt to: dissolve.

2) If I mixed starch in water I would expect the starch to: remain undissolved.

Explanation:

Hello,

In this case, since salt, which is commonly known as sodium chloride (NaCl) is an ionic compound, it is very likely to get dissolved in water, therefore, we would expect the salt to dissolve and form a liquid solution.

Moreover, since start is mainly composed by C-C, C-O and C-H bonds which are nonpolar, it we can say it is usually insoluble in water, therefore we will expect starch to remain undissolved but undergoing a process called gelatinization in which a suspension in formed until a slightly solid consistency.

Best regards.

4 0
3 years ago
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