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frozen [14]
3 years ago
12

. percent iron in a mixture that is 52.2% Fe2O3​

Chemistry
1 answer:
AVprozaik [17]3 years ago
8 0

Answer:

36.51%.

Explanation:

First find the percentage of iron in pure Fe2O3 using the  atomic masses of the elements:

=  (2 * 55.845) * 100 /  (2*55.845+ 3*15.999)

=  69.94 %.

So the percentage of iron in the mixture

=  52.2 * 0.6994

= 36.51 (answer).

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The atomic number of nitrogen is 7. How many protons, neutrons, and electrons make up an atom of Nitrogen-15?
earnstyle [38]
<h2><u>Answer:</u></h2>

A nonpartisan iota of Nitrogen has a mass of 18. There are 7 protons in the core of this iota. What number of neutrons, complete electrons, and valence electrons are available  

Nitrogen 15 has a nuclear mass of 15. The mass number is # protons in addition to # of neutrons, so for N-15 mass is 15 and the protons are dependably 7 so there must be 15-7=8 neutrons. N-15 has 7 electrons since it has 7 protons and p = e.

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Where in the mitochondria does the electron transport chain occur
wolverine [178]
I think it’s the inner membrane
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3 years ago
If 56.8 ml of bacl2 solution is needed to precipitate all the sulfate ion in a 554 mg sample of na2so4 (forming baso4), what is
IrinaVladis [17]
<span>0.0687 m The balanced equation is BaCl2 + Na2SO4 ==> BaSO4 + 2 NaCl Looking at the equation, it indicates that there's a 1 to 1 ratio of BaCl2 and Na2SO4 in the reaction. So the number of moles of each will be equal. Now calculate the number of moles of Na2SO4 we had. Start by looking up atomic weights. Atomic weight sodium = 22.989769 Atomic weight sulfur = 32.065 Atomic weight oxygen = 15.999 Molar mass Na2SO4 = 2 * 22.989769 + 32.065 + 4 * 15.999 = 142.040538 g/mol Moles Na2SO4 = 0.554 g / 142.040538 g/mol = 0.003900295 mol Molarity is defined as moles per liter, so let's do the division. 0.003900295 mol / 0.0568 l = 0.068667165 mol/l = 0.068667165 m Rounding to 3 significant figures gives 0.0687 m</span>
3 0
3 years ago
When 25.0 g of ch4 reacts completely with excess chlorine yielding 45.0 g of ch3cl, what is the percentage yield, according to c
Ber [7]

Taking into account definition of percent yield, the percent yield for the reaction is 57.08%.

<h3>Reaction stoichiometry</h3>

In first place, the balanced reaction is:

CH₄ + Cl₂ → CH₃Cl + HCl

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

  • CH₄: 1 mole
  • Cl₂: 1 mole
  • CH₃Cl: 1  mole
  • HCl:  1 mole

The molar mass of the compounds is:

  • CH₄: 16 g/mole
  • Cl₂: 70.9 g/mole
  • CH₃Cl: 50.45 g/mole
  • HCl:  36.45 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

  • CH₄: 1 mole ×16 g/mole= 16 grams
  • Cl₂: 1 mole ×70.9 g/mole= 70.9 grams
  • CH₃Cl: 1 mole ×50.45 g/mole= 50.45 grams
  • HCl: 1 mole ×36.45 g/mole= 36.45 grams

Mass of CH₃Cl formed

The following rule of three can be applied: if by reaction stoichiometry 16 grams of CH₄ form 50.45 grams of CH₃Cl, 25 grams of CH₄ form how much mass of CH₃Cl?

mass of CH_{3} Cl=\frac{25 grams of CH_{4}x 50.45grams of CH₃Cl }{16 grams of CH_{4}}

<u><em>mass of CH₃Cl= 78.83 grams</em></u>

Then, 78.83 grams of CH₃Cl can be produced from 25 grams of CH₄.

<h3>Percent yield</h3>

The percent yield is the ratio of the actual return to the theoretical return expressed as a percentage.

The percent yield is calculated as the experimental yield divided by the theoretical yield multiplied by 100%:

percent yield=\frac{actual yield}{theorical yield}x100

where the theoretical yield is the amount of product acquired through the complete conversion of all reagents in the final product, that is, it is the maximum amount of product that could be formed from the given amounts of reagents.

Percent yield for the reaction in this case

In this case, you know:

  • actual yield= 45 grams
  • theorical yield= 78.83 grams

Replacing in the definition of percent yields:

percent yield=\frac{45 grams}{78.83 grams}x100

Solving:

<u><em>percent yield= 57.08%</em></u>

Finally, the percent yield for the reaction is 57.08%.

Learn more about

the reaction stoichiometry:

brainly.com/question/24741074

brainly.com/question/24653699

percent yield:

brainly.com/question/14408642

#SPJ1

5 0
2 years ago
Please help me with this
klemol [59]

Answer: the answer is X.

Explanation:

Think of it as a graph with potential and kinetic energy

5 0
3 years ago
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