3 years ago

. percent iron in a mixture that is 52.2% Fe2O3

Chemistry

1 answer:

AVprozaik [17]3 years ago

8 0

Answer:

36.51%.

Explanation:

First find the percentage of iron in pure Fe2O3 using the atomic masses of the elements:

= (2 * 55.845) * 100 / (2*55.845+ 3*15.999)

= 69.94 %.

So the percentage of iron in the mixture

= 52.2 * 0.6994

= 36.51 (answer).

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3 years ago

. percent iron in a mixture that is 52.2% Fe2O3​

. percent iron in a mixture that is 52.2% Fe2O3