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Sergio039 [100]
3 years ago
12

Determine the number of protons, electron and neutrons present in an atom of magnesium

Chemistry
1 answer:
Elena L [17]3 years ago
5 0
Protons= 12, Electrons= 12, neutrons= 12
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How many ml of 12.0 M H2S04 are needed to make 500.0 ml of a 1.00 M solution? What happens to the freezing point and the boiling
lora16 [44]

Answer:

41.66 mL of 12.0 M sulfuric acid are needed.

Explanation:

Concentration of sulfuric acid solution taken =M_1=12.0M

Volume of the 12.0 M Solution = V_1

Concentration of required solution = M_2=1.00M

Volume of required 1.00 M solution = V_2=500.0 mL

M_1V_1=M_2V_2 (Dilution)

V_1=\frac{1.00 M\times 500.0 mL}{12.0 M}=41.66 mL

41.66 mL of 12.0 M sulfuric acid are needed.

The freezing point and the boiling point of a solvent when a non-volatile solute is dissolved in it decrease and increase respectively.

3 0
4 years ago
Give the formula for the compound formed when sulfur trioxide reacts with water.
Lera25 [3.4K]
Sulphur trioxide reacts with water to form a solution of sulphuric acid.
The equation describing this reaction is:
SO3 + H2O .............> H2SO4

Based on the above equation, the formula of the compound formed when sulphur trioxide reacts with water is: H2SO4
6 0
3 years ago
list the four quantum numbers from LAST electron of each of the following elements in their ground state: sodium, nitrogen, oxyg
Rasek [7]

Explanation:

The four quantum  numbers gives the position of the orbital, its spatial orientation, the shape of the orbital and the spin of the an electron in the orbital.

The principal quantum number(n) gives the main energy level in which the orbital is located; n = 1,2,3,4....

Azimuthal or secondary quantum number (l) gives the shape of the orbitals an they take values l = 0,1,2,3.... and their names are s for 0, p for 1, d for 2 and f for 3.

Magnetic quantum number gives the spatial orientation or degeneracy of the orbitals in the subshell.

Spin quantum number gives the spinning of the electrons

Electronic configuration:

Na = 1s² 2s² 2p⁶ 3s¹

   The last electron enters the 3s¹

           n = 3

            l = 0

           m = 0

            spin =+ or - \frac{1}{2}

N = 1s² 2s²  2p³

           last electron enters 2p³

              n = 2

              l = 1

               m = -1, 0, 1

               spin = + or - \frac{1}{2}

O = 1s² 2s² 2p²

    last electron enters  2p²

             n = 2

              l = 1

               m = -1, 0, 1

               spin = + or - \frac{1}{2}

Cl =1s² 2s² 2p⁶ 3s² 3p⁵

     last electron enters 3p⁵

               n = 3

              l = 1

               m = -1, 0, 1

               spin = + or - \frac{1}{2}

S = 1s² 2s² 2p⁶ 3s² 3p⁴

      last electron enters 3p⁴

               n = 3

              l = 1

               m = -1, 0, 1

               spin = + or - \frac{1}{2}

learn more:

Quantum number brainly.com/question/9288609

#learnwithBrainly

5 0
4 years ago
21. For each of the following precipitation reactions,
Phantasy [73]
I would say B.HS(aq)+NiSO4(aq)
6 0
3 years ago
What are 4 energy transfer
Klio2033 [76]
What kind of energy transfer
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