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2 years ago

Which of the following elements are non-reactive because their outer electron energy levels are full?

Physics

1 answer:

Marta_Voda [28]2 years ago

5 0

It would be Krypton, one of the noble gases.

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(FIRST TO ANSWER CORRECTLY WILL BE THE BRAINIEST!!!)How will the temperatures of the water in the beakers compare if an equal am

bulgar [2K]

Answer:

the answer is the temperatures of both beakers' water will increase by the same amount...

Explanation:

I know this because i just did it on study island

7 0

2 years ago

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A block of mass m is pushed up against a spring, compressing it a distance x, and the block is then released. The spring project

Gwar [14]

Answer:

$x' = 10 x$

Explanation:

By energy conservation we know that spring energy is converted into kinetic energy of the block

so we will have

$\frac{1}{2}kx^2 = \frac{1}{2}mv^2$

so we will have

$v = \sqrt{\frac{k}{m}}(x)$

now we will have same thing for another mass 4m which moves out with speed 5v

so we have

$5v = \sqrt{\frac{k}{4m}}(x')$

now from above two equations we have

$\frac{5v}{v} = \frac{x'}{2x}$

so we have

$x' = 10 x$

3 0

2 years ago

An investigator collects a sample of a radioactive isotope with an activity of 490,000 Bq.48 hours later, the activity is 110,00

Daniel [21]

Answer:

The correct answer is "22.27 hours".

Explanation:

Given that:

Radioactive isotope activity,

= 490,000 Bq

Activity,

= 110,000 Bq

Time,

= 48 hours

As we know,

⇒ $A = A_0 e^{- \lambda t}$

or,

⇒ $\frac{A}{A_0}=e^{-\lambda t}$

By taking "ln", we get

⇒ $ln \frac{A}{A_0}=- \lambda t$

By substituting the values, we get

⇒ $-ln \frac{110000}{490000} = -48 \lambda$

⇒ $-1.4939=-48 \lambda$

$\lambda = 0.031122$

As,

⇒ $\lambda = \frac{ln_2}{\frac{T}{2} }$

then,

⇒ $\frac{ln_2}{T_ \frac{1}{2} } =0.031122$

⇒ $T_\frac{1}{2}=\frac{ln_2}{0.031122}$

$=22.27 \ hours$

3 0

2 years ago

Transduction of lower frequency sound waves occurs at the __________ of the cochlea.

kiruha [24]

I got inner ear for my answer if wrong sorry

4 0

3 years ago

Read 2 more answers

You are given two converging lenses to build a compound microscope. Lens A has focal length 0.50 cm and lens B has focal length

siniylev [52]

Answer:

The lens to be used for the objective is lens A

Explanation:

The objective of a compound microscope

The focal length of the lens used for the objective = 1/(magnification obtained)

The focal length of most modern is equal to the tube length

The range of sizes for the focal length of a microscope is between 2 mm and 40 mm

Therefore, the appropriate lens to be used for the objective of the compound is lens A that has a focal length of 0.50 cm = 5 mm

6 0

2 years ago