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4 years ago

15

Autotrophic plants do not require which of the following? solar energy carbon dioxide water oxygen NextReset

1 answer:

alukav5142 [94]4 years ago

4 0

<span>Autotrophic plants do not require "Oxygen" as it is a waste product of the process of photosynthesis which they do.

In short, Your Final Answer would be Option D

Hope this helps!</span>

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Which of these describes the part of the water cycle happening at D

tino4ka555 [31]

The answer is Runoff.

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3 years ago

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Nodes and antinodes.are part of an _____ wave<br><br> A active <br> B standing

mel-nik [20]

It could be A :) not sure tho

5 0

3 years ago

The roller coaster car has a mass of 700 kg, including its passenger. If it is released from rest at the top of the hill A, dete

sweet [91]

Answer:

$h = 18.75 m$

Now when it will reach at point B then its normal force is just equal to ZERO

$N_B = 0$

$F_n = 1.72 \times 10^4$

Explanation:

Since we need to cross both the loops so least speed at the bottom must be

$v = \sqrt{5 R g}$

also by energy conservation this is gained by initial potential energy

$mgh = \frac{1}{2}mv^2$

$v = \sqrt{2gh}$

so we will have

$\sqrt{2gh} = \sqrt{5Rg}$

now we have

$h = \frac{5R}{2}$

here we have

R = 7.5 m

so we have

$h = \frac{5(7.5)}{2}$

$h = 18.75 m$

Now when it will reach at point B then its normal force is just equal to ZERO

$N_B = 0$

now when it reach point C then the speed will be

$mgh - mg(2R_c) = \frac{1}{2]mv_c^2$

$v_c^2 = 2g(h - 2R_c)$

$v_c = 13.1 m/s$

now normal force at point C is given as

$F_n = \frac{mv_c^2}{R_c} - mg$

$F_n = \frac{700\times 13.1^2}{5} - (700 \times 9.8)$

$F_n = 1.72 \times 10^4$

7 0

4 years ago

You work at a garden store for the summer, and you lift a 14 kg bag of fertilizer with a force of 227 N.

nika2105 [10]

Answer:

(a) Acceleration of the bag will be a=16.214m/sec^2

(B) Weight of the bag will be 137.2 N

Explanation:

We have given mass of the bag m = 14 kg

Force with which bag is lifted = 227 N

(A) According to newtons law we force is equal to F = ma , here m is mass and a is acceleration

So $227=14\times a$

$a=16.214m/sec^2$

(b) Acceleration due to gravity $g=9.8m/sec^2$

We know that weight is given by W = mg , here m is mass and g is acceleration due to gravity

So weight $W=mg=14\times 9.8=137.2N$

So weight of the bag will be 137.2 N

8 0

4 years ago

Consider a 7 m stretched string that is clamped at both ends. What is the longest wavelength standing wave that it can support (

user100 [1]

A vibrating stretched string has nodes or fixed points at each end. The string will vibrate in its fundamental frequency with just one anti node in the middle - this gives half a wave.

$l=\frac{\lambda }{2}$

Rearranging for the wavelength

$\lambda=2l$

$\lambda =2(7)$

$\lambda = 14m$

Therefore the longest wavelength standing wave that it can support is 14m

7 0

4 years ago