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posledela
3 years ago
7

Which activity would be an appropriate first step

Physics
1 answer:
andriy [413]3 years ago
3 0

Answer:

B. Researching the problem, using information from a variety of sources

Explanation:

First you must create a hypothesis because with out a hypothesis you can’t do the experiment. Then you have to do some research on your problem/ hypothesis from reliable sources. After have your research you can organize your data with a data table or chart. Then when have your research look for the independent and dependent variable and the control. Then you have to make a conclusion based on multiple experimental trials then repeat the experiment and if it ends up different from the first then something is wrong and that means that you did something wrong. Hopefully this helps you :)

pls mark brainlest ;)

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Can you ever absolutely prove that a hypothesis is correct? Explain.
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8 0
3 years ago
LOTS OF POINTSA rocket of mass 40 000 kg takes off and flies to a height of 2.5 km as its engines produce 500 000 N of thrust.
Svetradugi [14.3K]

Answer:

i) E = 269 [MJ]    ii)v = 116 [m/s]

Explanation:

This is a problem that encompasses the work and principle of energy conservation.

In this way, we establish the equation for the principle of conservation and energy.

i)

E_{k1}+W_{1-2}=E_{k2}\\where:\\E_{k1}= kinetic energy at moment 1\\W_{1-2}= work between moments 1 and 2.\\E_{k2}= kinetic energy at moment 2.

W_{1-2}= (F*d) - (m*g*h)\\W_{1-2}=(500000*2.5*10^3)-(40000*9.81*2.5*10^3)\\W_{1-2}= 269*10^6[J] or 269 [MJ]

At that point the speed 1 is equal to zero, since the maximum height achieved was 2.5 [km]. So this calculated work corresponds to the energy of the rocket.

Er = 269*10^6[J]

ii ) With the energy calculated at the previous point, we can calculate the speed developed.

E_{k2}=0.5*m*v^2\\269*10^6=0.5*40000*v^2\\v=\sqrt{\frac{269*10^6}{0.5*40000} }\\ v=116[m/s]

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3 years ago
Which of the following statements BEST explains why ball-and-socket joints have the greatest range of motion?
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Answer:

its d on edge c:

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