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3 years ago

15

A toy store uses 3/16 of its space for trains. It uses 1/16 of its space for boats. How much more space is used for trains than

for boats? Simplify the answer if possible.

1 answer:

katen-ka-za [31]3 years ago

5 0

3/16 - 1/16 = (3-1) / 16 = 2/16 = 1/8

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Please help as soon as possible

Mice21 [21]

1 kilometer = 1000 meters so 12 kilometers = 12000 meters

10 laps (400 meters/lap) = 4000 meters

12000/4000 = 3

Answer: 3 days

4 0

3 years ago

In preparing a certain ointment, a pharmacist used 28.35 g of zinc oxide instead of the 31.1 g called for. Calculate the percent

Vilka [71]

Answer: 9.70%

Step-by-step explanation:

The formula to find the percentage error is given by :-

$\%\text{ error}=\dfrac{|\text{Estimate-Actual}|}{\text{Actual}}\times100$

Given : Actual mass of zinc oxide used by pharmacist = 28.35 g

Estimated mass of zinc oxide used by pharmacist =31.1 g

Now, $\%\text{ error}=\dfrac{|31.1-28.35|}{28.35}\times100$

i.e. $\%\text{ error}=\dfrac{2.75}{28.35}\times100$

i.e. $\%\text{ error}=9.70017636684\approx9.70\%$

Hence, the percentage of error on the basis of the desired quantity.= 9.70%

5 0

3 years ago

What is the M.A.D of 1,1,1,1,5?

algol [13]

I think it is 3.6 .......

8 0

3 years ago

What is 4+5=20 +34+56

enyata [817]

This question’s answer is no solution, unless there was a typo. If there was, comment, and i’ll Answer it!

7 0

3 years ago

Read 2 more answers

jonny [76]

keeping in mind that parallel lines have exactly the same slope, let's check for the slope of the equation above

$y = \stackrel{\stackrel{m}{\downarrow }}{2}x-5\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}$

so we're really looking for the equation of a line whose slope is 2 and passes through (4 , -3)

$(\stackrel{x_1}{4}~,~\stackrel{y_1}{-3})\qquad \qquad \stackrel{slope}{m}\implies 2 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-3)}=\stackrel{m}{2}(x-\stackrel{x_1}{4}) \\\\\\ y+3=2x-8\implies y=2x-11$

5 0

3 years ago