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Yuri [45]
3 years ago
13

A 15 kg television sits on a shelf at a height of 0.3 m. How much gravitational potential energy is added to the television when

it is lifted to a shelf of height 1.0 m?
Physics
1 answer:
tatuchka [14]3 years ago
7 0
4.5 and then your units I forgot that part but the answer is 4.5<span />
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Once juno reaches jupiter, what is the minimum amount of time it takes for the transmitted signals to travel from the spacecraft
Komok [63]

In very very very round figures . . .

-- Jupiter is about 5.2 times as far from the sun as the earth is.

-- So when Jupiter and the EARTH are aligned in both orbits, Jupiter is about

(4.2) x (150 million kilometers) = 630 million kilometers

Time = (distance) / (speed)

The speed of light and radio is 300,000 km/second

Time = (630 million / 300 thousand)

<em>Time = 2,100 seconds</em>

That's 35 minutes.

4 0
3 years ago
Read 2 more answers
Calculate the average velocity of a dancer who moves 5 m toward the left of the stage over the course of 15 s. ** Velocity = dis
Alex73 [517]

Answer:

B

Explanation:

Velocity=disp/time

V=5m/15s

V=1/3 m/s

3 0
4 years ago
What happens to light when it changes speed?
Brut [27]
Hey there!

When light changes speed, it REFRACTS.
Your answer is going to be option C.

Hope this helps you.
Have a great day!
5 0
3 years ago
A 5 kg block is sliding down a plane inclined at 30^0 with a constant velocity of 4 m/s. To determine the coefficient of frictio
Leya [2.2K]

Answer:

The necessary information is if the forces acting on the block are in equilibrium

The coefficient of friction is 0.577

Explanation:

Where the forces acting on the object are in equilibrium, we have;

At constant velocity, the net force acting on the particle = 0

However, the frictional force is then given as

F = mg sinθ

Where:

m = Mass of the block

g = Acceleration due to gravity and

θ = Angle of inclination of the slope

F = 5×9.81×sin 30 = 24.525 N

Therefore, the coefficient of friction is given as

24.525 N = μ×m×g × cos θ = μ × 5 × 9.81 × cos 30 = μ × 42.479

μ × 42.479 N= 24.525 N

∴ μ = 24.525 N ÷ 42.479 N = 0.577

3 0
4 years ago
Read 2 more answers
This is a two part question: What is the force of friction acting on a 100 kg steel slab at rest on a steel floor?
Crazy boy [7]
1) 0N... friction opposes the motion of an object, since the block is at rest there is no motion thus no friction

2) F=ma
= (5.5kg)(30m/s)
=165 N
7 0
3 years ago
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