Help is requested. Will give brainliest to anyone who answers correctly.
1 answer:
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Answer:
i). Inverted
ii). Magnification of the image = -0.5
iii). Real
Explanation:
As shown in the ray diagram attached,
An object AB has been placed in front of converging lens (convex lens) at u = 30 cm.
F (Focus) of the lens is at 10 cm. So F = 10 cm
By analyzing the ray diagram we can measure the distance of the image on the other side of the lens (By counting the small blocks of the graph)
V = 15 cm
Characteristics of the image is:
i) Inverted
ii) Magnification of the image =
= -0.5
ii) Real
Answer:
<em>1.228 x </em><em> mm </em>
<em></em>
Explanation:
diameter of aluminium bar D = 40 mm
diameter of hole d = 30 mm
compressive Load F = 180 kN = 180 x N
modulus of elasticity E = 85 GN/m^2 = 85 x Pa
length of bar L = 600 mm
length of hole = 100 mm
true length of bar = 600 - 100 = 500 mm
area of the bar A = =
= 1256.8 mm^2
area of hole a = =
= 549.85 mm^2
Total contraction of the bar =
total contraction =
==> = <em>1.228 x </em>
<em> mm </em>