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MrRissso [65]
3 years ago
15

A car was moving at 14 m/s After 30 s, its speed increased to 20 m/s. What was the acceleration during this time ( need help fas

t!!!)
Physics
1 answer:
Arada [10]3 years ago
7 0

Answer:let initial velocity u=14m/s

Final velocity v=20m/s

Time taken t=30

Acceleration =a

V=u +at

a= (20-14)/30

a=0.2m/s^2

Explanation:

Acceleration is the change in velocity with respect to time.

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Ierofanga [76]

Answer:

External force on him will be 112 N

Explanation:

We have given the mass of the sprinter m =70 kg

Acceleration of the sprinter a=1.6m/sec^2

We have to find the net external force

According to second law of motion force = mass ×acceleration

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So F=70\times 1.6=112 N

So external force will be 112 N

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What is the suitable condition for the superconductivity and high resista (a) Weak phonon-phonon interactions (b) No interaction
Readme [11.4K]

Answer:

(d) A strong electron-phonon interaction

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7 0
3 years ago
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