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2 years ago

15

A car was moving at 14 m/s After 30 s, its speed increased to 20 m/s. What was the acceleration during this time ( need help fas

t!!!)

1 answer:

Arada [10]2 years ago

7 0

Answer:let initial velocity u=14m/s

Final velocity v=20m/s

Time taken t=30

Acceleration =a

V=u +at

a= (20-14)/30

a=0.2m/s^2

Explanation:

Acceleration is the change in velocity with respect to time.

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What are examples of a solution in solids, liquids, and gases

Nina [5.8K]

Answer:

Solid: metal alloy

Liquid: beer

Gas: Air

Explanation:

A solution is a type of mixture where the solvent and solute are homogeneously mixed. Homogeneous mixture means that the solute shouldn't be able to be seen with the naked eye, filtered and stable enough.

Metal alloy will be an example of a solution in solid-state. Beer is a solution made of liquid alcohol and liquid water. Air mostly composed of nitrogen, but it has oxygen, carbon dioxide, and many other substances in gaseous form.

3 0

2 years ago

An undersea research chamber is spherical with an external diameter of 5.50 m . The mass of the chamber, when occupied, is 87600

dmitriy555 [2]

Answer:

the buoyant force on the chamber is F = 7000460 N

Explanation:

the buoyant force on the chamber is equal to the weight of the displaced volume of sea water due to the presence of the chamber.

Since the chamber is completely covered by water, it displaces a volume equal to its spherical volume

mass of water displaced = density of seawater * volume displaced

m= d * V , V = 4/3π* Rext³

the buoyant force is the weight of this volume of seawater

F = m * g = d * 4/3π* Rext³ * g

replacing values

F = 1025 kg/m³ * 4/3π * (5.5m)³ * 9.8m/s² = 7000460 N

Note:

when occupied the tension force on the cable is

T = F buoyant - F weight of chamber = 7000460 N - 87600 kg*9.8 m/s² = 6141980 N

4 0

3 years ago

Calculate the radius of the orbit of a proton moving at 2.2x10^6 m/s in a magnetic field 0.7 T where v and B are perpendicular.

Juliette [100K]

Answer:

3.28 cm

Explanation:

To solve this problem, you need to know that a magnetic field B perpendicular to the movement of a proton that moves at a velocity v will cause a Force F experimented by the particle that is orthogonal to both the velocity and the magnetic Field. When a particle experiments a Force orthogonal to its velocity, the path it will follow will be circular. The radius of said circle can be calculated using the expression:

r = $\frac{mv}{qB}$

Where m is the mass of the particle, v is its velocity, q is its charge and B is the magnitude of the magnetic field.

The mass and charge of a proton are:

m = 1.67 * 10^-27 kg

q = 1.6 * 10^-19 C

So, we get that the radius r will be:

r = $\frac{1.67 * 10^-27 kg * 2.2*10^6 m/s}{1.6 * 10^-19 C* 0.7 T}$ = 0.0328 m, or 3.28 cm.

8 0

3 years ago

Bro what does this mean ? I don’t get this

zhannawk [14.2K]

CO2 is carbon dioxide a colorless gas

3 0

2 years ago

Read 2 more answers

The spectral distribution of the radiation emitted by a diffuse surface may be approximated as follows. HW 2 Q2 (a) What is the

Ronch [10]

Answer:

a)<em> 2000 W/m² </em><em>; </em>b) 636.94 W/m<em>².sr ; </em><em>c) </em>0.5

Explanation:

a)

The formula for calculation of total emissive power is:

Total emissive power = E = $\int\limits^\alpha_0$ E'<em>λdλ</em>

<em> </em>= $\int\limits^a_0$ (0)d<em>λ + </em> $\int\limits^b_a$ (100)d<em>λ + </em> $\int\limits^c_b$ (200)d<em>λ + </em> $\int\limits^d_c$ (100)d<em>λ </em> $\int\limits^e_d$ (0)d<em>λ</em>

<em>where a = 5; b = 10; c = 15; d = 20; e = 25</em>

<em> = 0 +100(10-5) + 200(15-10) +100(20-15) + 0</em>

<em> = 2000 W/m²</em>

b)

The formula for total intensity of radiation is:

I $_{e}$ = E/π = 200/3.14 = 636.94 W/m<em>².sr </em>

<em>c)</em>

Fo submissive power leaving the surface in range π/4 ≤θ≤π/2

[E(π/4 ≤θ≤π/2)]/E = $\int\limits^f_0$ $\int\limits^g_0$ $\int\limits^i_h$ Icosθsinθ dθdΦdλ

where f = infinity, g=2π, h=π/4, i=π/2

By simplifying, we get

= (-1/2)[cos(2π/2)-cos(2π/2)]

= -0.5(-1-0)

=0.5

8 0

3 years ago