Answer:
10432.19076 m
Explanation:
= Wavelength = 660 nm
d = Diameter of pupils = 6 mm
s = Distance between lights = 1.4 m
L = Distance from observer
From Rayleigh's criteria we have

As
is small 
So, the equation becomes

The car is 10432.19076 m from me
Vi=0
T=3.07s
D=46m
A=?
A=2(d)/t ^2
2(46)/3.07^2=9.8m/s^2
Answer:
The correct answer is B
Explanation:
To calculate the acceleration we must use Newton's second law
F = m a
a = F / m
To calculate the force we use the defined pressure and the radiation pressure for an absorbent surface
P = I / c absorbent surface
P = F / A
F / A = I / c
F = I A / c
The area of area of a circle is
A = π r²
We replace
F = I π r² / c
Let's calculate
F = 8.0 10⁻³ π (1.0 10⁻⁶)²/3 10⁸
F = 8.375 10⁻²³ N
Density is
ρ = m / V
m = ρ V
m = ρ (4/3 π r³)
m = 4500 (4/3 π (1 10⁻⁶)³)
m = 1,885 10⁻¹⁴ kg
Let's calculate the acceleration
a = 8.375 10⁻²³ / 1.885 10⁻¹⁴
a = 4.44 10⁻⁹ m/s² absorbent surface
The correct answer is B
Answer:
Explanation:
frequency of vibration
n = 40 / 22.3 per second.
= 1.794 per second
velocity of wave v = 369 / 13.5 cm / s
= 27.33 cm / s
wavelength = velocity / frequency
= 27.33 / 1.794
= 15.23 cm