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inna [77]
3 years ago
12

Two points are located on a rigid wheel that is rotating with decreasing angular velocity about a fixed axis. Point A is located

in the rim of the wheel and pint B is halfway between the rim and the axis. Which one of the following statements concerning this situation is true?
1. The angular velocity at point A is greater than that of point B
2. Both points have the same centripetal acceleration
3. Both points have the same tangential acceleration4. Both points have the same instantaneous angular velocity
5. Each second, point A turns through a greater angle than point B
Physics
1 answer:
Nata [24]3 years ago
4 0

Answer:

4. Both points have the same instantaneous angular velocity

Explanation:

Angular velocity is a measure of the the number of rotations per unit time. This does not depend on the radius of the wheel. Hence, all points on the wheel have the same angular velocity. This invalidates option 1.

The centripetal acceleration is given by the product to the square of the angular velocity and the radius or distance from the centre. A and B are located at different distances from the centre. Hence, they have different centripetal acceleration. This invalidates option 2.

The tangential acceleration depends on the linear velocity which itself is a product of the angular velocity and the distance from the centre. Hence, it is different for both points because they are at different distances from the centre.

Since both A and B are fixed points on the wheel, they move through equal angles in the same time. In fact, for any other fixed point, they all move through the same angle in the same time. This invalidates option 5.

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A lens is used to make an image of magnification -1.50. The image is 30.0 cm from the lens. What is the object’s distance (unit=
photoshop1234 [79]

Answer:

The object distance is 20cm

Explanation:

Given

Magnification = -1.5

Image distance = 30 cm.

Required

Object Distance

We can calculate the object's distance using magnification formula;

M = -V/U

Where M = Magnification = -1.50

V = Image Distance = 30cm

U = Object Distance

Substitute the above parameters in the formula above.

-1.50 = -30/U

Multiply both sides by -1

-1.50 * -1 = -30/U * -1

1.50 = 30/U

Multiply both sides by U

1.50 * U = 30/U * U

1.50U = 30

Divide through by 1.50

1.50U/1.50 = 30/1.50

U = 30/1.50

U = 20cm

Recall that U represented the object distance.

Hence, the object distance is 20cm

5 0
4 years ago
A coffee filter of mass 1.5 grams dropped from a height of 3 m reaches the ground with a speed of 0.7 m/s. How much kinetic ener
Mademuasel [1]

The kinetic energy gained by the air molecules is 0.0437 J                

<h3 />

Given:

Mass of a coffee filter, m = 1.5 g

Height from which it is dropped, h = 3 m

Speed at ground, v = 0.7 m/s

Initially, the coffee filter has potential energy. It is given by :

P =mgh

P = 1.5 × 10⁻³ kg × 9.8 m/s² × 3m

P = 0.0441 J

Finally, it will have kinetic energy. It is given by :

E= \frac{1}{2} mv^{2}

E= \frac{1}{2}×1.4 × 10⁻³ × (0.7)²

E = 0.000343 J

The  kinetic energy Kair did the air molecules gain from the falling coffee filter is :

E = 0.000343 -  0.0441

  = 0.0437 J

So, the kinetic energy Kair did the air molecules gain from the falling coffee filter is 0.0437 J

Learn more about kinetic energy here:

brainly.com/question/8101588

#SPJ4

8 0
2 years ago
Every surface has different ____________________ of friction.
dedylja [7]

Answer:

amounts

Explanation:

every surface has different amounts of friction

hope this helps :) plz brainliest?

3 0
3 years ago
What is the mass of an object that has a weight of 52N? (n=newtons)<br><br>Answer is in kilograms
polet [3.4K]
Hi there!

The answer you are looking for.....



<span>5.3025kg!</span>





Hope this helps you!

Have a great day!

8 0
3 years ago
An electron moves through a uniform electric field E = (2.00î + 5.40ĵ) V/m and a uniform magnetic field B = 0.400k T. Determine
EleoNora [17]

Answer:a=1.75\times 10^{21}\left ( 2\hat{i}5.08\hat{j}\right )

Explanation:

Given

Electric Field \vec{E}=2\hat{i}+5.4\hat{j}

\vec{B}=0.4\hat{k}\ T

velocity \vec{v}=8\hat{i} m/s

mass of electron m=9.1\times 10^{-31} kg

Force on a charge Particle moving in Magnetic Field

F=e\left [ \vec{E}+\left ( \vec{v}\times \vec{B}\right )\right ]

a=\frac{e\left [ \vec{E}+\left ( \vec{v}\times \vec{B}\right )\right ]}{m}

a=\frac{1.6\times 10^{-19}\left [ 2\hat{i}+5.4\hat{j}+\left ( 8\hat{i}\times 0.4\hat{k}\right )\right ]}{9.1\times 10^{-31}}  

a=1.75\times 10^{21}\left ( 2\hat{i}+5.08\hat{j}\right )\ m/s^2

7 0
3 years ago
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