Answer:
The speed of the water shoot out of the hole is 20 m/s.
(d) is correct option.
Explanation:
Given that,
Height = 20 m
We need to calculate the velocity
Using formula Bernoulli equation
Where,
v₁= initial velocity
v₂=final velocity
h₁=total height
h₂=height of the hole from the base
Put the value into the formula
Hence, The speed of the water shoot out of the hole is 20 m/s.
Answer: So finally, the dimensional formula of the radius of gyration will be written as: [M0LT0]. The power of zero on the dimension of the mass and time shows that the mass and the time dimensions are zero for the radius of gyration. Hope this helps (:
The horizontal speed of the object 1.0 seconds later is 1) 5.0 m/s.
Explanation:
The motion of an object thrown horizontally off a cliff is a projectile motion, which follows a parabolic path that consists of two independent motions:
- A uniform motion (constant velocity) along the horizontal direction
- An accelerated motion with constant acceleration (acceleration of gravity) in the vertical direction
This means that the horizontal speed of an object in projectile motion does not change, and remains constant during the whole motion.
Since in this case the object has been launched with a horizontal speed of
v = 5.0 m/s
this means that this speed will remain constant during the motion, so its horizontal speed 1.0 s later is also 5.0 m/s.
Learn more about projectile motion:
brainly.com/question/8751410
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To get x on its own, you times the 3 over to the other side so the 3 cancels out on the LHS.
~ x greater than or equal to -18
(C)
