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Hatshy [7]
1 year ago
15

This lab is investigating the relationship between mass, ________, and momentum.

Physics
1 answer:
Sav [38]1 year ago
7 0

This lab is investigating the relationship between mass, <u>Speed </u>, and momentum.

Momentum is manufactured from the mass and speed of an object. it's miles a vector quantity, owning a significance and a direction. If m is an object's mass and v is its speed, then the object's momentum is p.

Momentum in an easy way is a quantity of movement. right here amount is measurable because if an item is moving and has mass, then it has momentum. If an object no longer flows then it has no momentum. however, in regular existence, it has an important but many people didn't understand it.

Momentum gives the connection between the mass, pace, and direction of an object. Any exchange in momentum results in pressure. So, an exchange in momentum is used to determine the force appearing upon the item.

Learn more about momentum here:-brainly.com/question/1042017

#SPJ1

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Create a series circuit with a 10-volt battery and four 10-ohm resistors, as shown. Measure the current. A. Based on the voltage
iogann1982 [59]

Answer:

0.25 A

Resistance= 40 ohms

Explanation:

The first, and perhaps most important, the relationship between current, voltage, and resistance is called Ohm's Law, discovered by Georg Simon Ohm and published in his 1827 paper. Ohm's law states that the current through a conductor between two points is directly proportional to the voltage across the two points. Introducing the constant of proportionality, the resistance, one arrives at the usual V=IR. Any Electrical device or component that obeys “Ohms Law” that is, the current flowing through it is proportional to the voltage across it ( I α V ), such as resistors or cables, are said to be “Ohmic” in nature.

Since we are not in a laboratory, we can not experimentally measure the current but it can be calculated from ohm's law.

Given that the four resistors are connected in series and

Req= R1 + R2 + R3 + R4

Since all are four ohm resistors

Req= 10 + 10+10+10 = 40ohms

Then;

V= 10 V

R= 40ohms

I= ???

From;

V=IR

I= 10/40

I= 0.25 A

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skin cancer and it cause to lost transportating process

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Do you believe that a patient with late-stage Alzheimer's
strojnjashka [21]

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6 0
2 years ago
A moving particle encounters an external electric field that decreases its kinetic energy from 9970 eV to 6340 eV as the particl
marusya05 [52]

Answer:

q = -1.61x10⁻¹⁷ C

Explanation:

The charge of the particle can be found using the definition of the work done by electric force:  

W = -q\Delta V         (1)

<u>Where</u>:

q: is the charge

ΔV: is the difference in electric potential

The work is also equal to:

W = E_{p_{A}} - E_{p_{B}}    (2)

<u>Where</u>:

E_{p_{A}} and E_{p_{B}} are the electric potential energy of the points A and B, respectively.

Now, by conservation of energy we have:

K_{A} + E_{p_{A}} = K_{B} + E_{p_{B}}     (3)

<u>Where</u>:  

K_{A} and K_{B} are the kinetic energy of the points A and B, respectively.

Rearranging equation (3):  

K_{B} - K_{A} = E_{p_{A}} - E_{p_{B}}      

K_{B} - K_{A} = W

K_{B} - K_{A} = -q\Delta V

Solving the above equation for q:

q = -\frac{K_{B} - K_{A}}{V_{B} - V_{A}} = -\frac{6340 eV - 9970 eV}{19.0 V - 55.0 V} = -100.83 e \cdot \frac{1.6 \cdot 10^{-19} C}{1 e} = -1.61 \cdot 10^{-17} C                                              

Therefore, the charge of the particle is -1.61x10⁻¹⁷ C.

I hope it helps you!

7 0
3 years ago
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