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3 years ago

1.) When the acceleration is zero, what can you say about the velocity of an object?

Physics

1 answer:

Paraphin [41]3 years ago

6 0

Answer:

it is either constant or zero

Explanation:

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Water is pouring into a conical tank at the rate of 8 cubic feet per minute. If the height of the tank is 10 feet and the radius

iren [92.7K]

Answer:

$\frac{25}{8\pi}ft/min$

Explanation:

We are given that

$\frac{dV}{dt}=8 ft^3/min$

Height of tank=h=10 ft

Radius of tank, r=4 feet

We have to find the dh/dt when the water is 4 feet deep.

$\frac{r}{h}=\frac{4}{10}=\frac{2}{5}$

$r=\frac{2}{5}h$

Volume of cone , $V=\frac{1}{3}\pi r^2 h$

Substitute the values

Volume of cone , $V=\frac{1}{3}\pi(\frac{2}{5}h)^2h=\frac{4}{75}\pi h^3$

Differentiate w.r.t t

$\frac{dV}{dt}=\frac{12}{75}\pi\times h^2\times \frac{dh}{dt}$

Substitute the values

$8=\frac{12}{75}\times\pi (4)^2\times \frac{dh}{dt}$

$\frac{dh}{dt}=\frac{8\times 75}{12\times 16\pi}=\frac{25}{8\pi}ft/min$

3 0

4 years ago

Consider a system consisting of two Einstein solids, A and B, each containing N= 10 oscillators, and sharing a total of q= 20 un

Daniel [21]

Answer:Gg

Explanation:

7 0

3 years ago

Match the labeled parts of the cell to their functions. Packages and transports materials out of the cell: Breaks down sugar to

Licemer1 [7]

The parts of the cell are mitochondria, lysosomes, ribosomes etc. Their functions are as follows :

(1) Vesicle is a one of the large structure within the cell. Its function is to transfer materials out of the cell.

(2) Mitochondria is also called the power house of the cell. Its function is to break down sugar to supply energy for the cell.

(3) Lysosomes are the suicidal bag of the cell. It breaks down waste and other materials of the cell.

(4) Endoplasmic reticulum helps to produce, process and transport proteins in vesicles to the Golgi apparatus.

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3 years ago

If an R = 1-kΩ resistor, a C = 1-μF capacitor, and an L = 0.2-H inductor are connected in series with a V = 150 sin (377t) volts

fgiga [73]

Answer

given,

R = 1-kΩ = 1000 Ω

C = 1-μF

L = 0.2-H

V = V_max sin( ω t)

comparing

V = 150 sin ( 377 t)

ω = 377

$\chi_c = \dfrac{1}{\omega C}$

$\chi_c = \dfrac{1}{377 \times 1 \times 10^{-6}}$

$\chi_c = 2652.5\Omega$

$\chi_L =377 \times 0.2$

$\chi_L =75.4\ \Omega$

Impedance,

$Z = \sqrt{R^2+(\chi_L-\chi_c)^2}$

$Z = \sqrt{1000^2+(75.4 -2652.5)^2}$

Z = 2764.3 Ω

now,

V_{max} = 150 V

$I_{max} = \dfrac{V}{Z}$

$I_{max} = \dfrac{150}{2764.3}$

$I_{max} = 0.0543$

$I_{max} = 54.3\ mA$

3 0

3 years ago

using newtons law a force of 250N is applied to an object that accelerates at a rate of 5M/s2 what is the mass of the object?

AURORKA [14]

Answer:

50 kg

Explanation:

F = ma

250 N = m (5 m/s²)

m = 50 kg

7 0

3 years ago