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lubasha [3.4K]
3 years ago
10

How many hydrogen atoms are present in a hydrocarbon chain of five carbons joined to each other by single covalent bonds?

Chemistry
1 answer:
zhenek [66]3 years ago
5 0

Answer:

12 hydrogen atoms are present.

Explanation:

The hydrocarbon is an alkane as it contains single covalent bonds.

The first carbon attaches to 3 hydrogen atoms, the second to fourth carbon attaches to 2 hydrogen atoms each and the last (fifth) carbon have 3 hydrogen atoms.

The Alkane compound is called PENTANE with molecular formula C5H12.

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The wavelength of the blue light given off by a mercury vapor street lamp is 457 nm. What is the frequency of this light in hert
Fed [463]

Answer:

6.56×10¹⁴ Hz

Explanation:

From the question given above, the following data were obtained:

Wavelength = 457 nm

Frequency =?

Next, we shall convert 457 nm to metre (m). This can be obtained as follow:

1 nm = 1×10¯⁹ m

Therefore,

457 nm = 457 nm × 1×10¯⁹ m / 1 nm

457 nm = 4.57×10¯⁷ m

Thus, 457 nm is equivalent to 4.57×10¯⁷ m

Finally, we shall determine the frequency of the blue light as follow:

Wavelength = 4.57×10¯⁷ m

Velocity of light = 3×10⁸ m/s

Frequency =?

Velocity = wavelength x frequency

3×10⁸ = 4.57×10¯⁷ × frequency

Divide both side by 4.57×10¯⁷

frequency = 3×10⁸ / 4.57×10¯⁷

frequency = 6.56×10¹⁴ Hz

Therefore, the frequency of the blue light is 6.56×10¹⁴ Hz

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3 years ago
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boyakko [2]

Answer:

basalt

Explanation:

4 0
3 years ago
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The up and down movement of gases and liquids caused by heat transfer?
AnnZ [28]

Answer:

B.

Explanation:

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4 years ago
Calculate the concentration of buffer components present in 210.00 mL of a buffer solution that contains 0.300 M NH4Cl and 0.300
Lynna [10]

Answer:

[NH3] = 0.270M

[NH4Cl] = 0.327M

Explanation:

The HNO3 will react with the weak base, NH3, as follows:

HNO₃ + NH₃ → NH₄⁺ + NO₃⁻

Initial moles of each specie of the buffer:

NH3 = NH4⁺ 0.210L * (0.300mol/L) = 0.063moles

The moles added of HNO3 = Additional moles of NH4Cl and the moles substracted of NH3:

0.001L * (6mol / L) = 0.006 moles.

After the addition:

Moles NH3 = 0.063mol - 0.006mol = 0.057moles

Moles NH4Cl = 0.063mol + 0.006mol = 0.0069moles

And their concentrations are:

[NH3] = 0.057moles / 0.211L = 0.270M

[NH4Cl] = 0.069moles / 0.211L = 0.327M

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4 years ago
ANSWER ASAP GIVING BRAINIEST FIVE STARS AND HEART!
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Answer:

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Explanation:

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