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2 years ago

How many moles are in 8.2 x 10^22molecules of N2I6?

Chemistry

1 answer:

stiks02 [169]2 years ago

6 0

Answer:

First, find out how many moles of N2I6 you have. Then convert that to grams.

molar mass N2I6 = 789 g

moles N2I6 = 8.2x1022 molecules N2I6 x 1 mole/6.02x1023 molecules = 1.36x10-1 moles = 0.136 moles

grams N2I6 = 0.136 moles x 789 g/mole = 107 g = 110 g (to 2 significant figures)

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Which liquid has the highest vapor pressure at 75°C?

Temka [501]

Answer:

1) Ethanol

Explanation:

If we will have interactions we will need more energy to break them in order to go from liquid to gas. If we need more energy, therefore, the temperature will be higher.

In this case, we can discard the propanone because this molecule don't have the ability to form hydrogen bonds. (Let's remember that to have hydrogen bonds we need to have a hydrogen bond to a heteroatom, O, N, P or S).

Then we have to analyze the hydrogen bonds formed in the other molecules. For ethanol, we will have only 1 hydrogen bond. For water and ethanoic acid, we will have 2 hydrogen bonds, therefore, we can discard the ethanol.

For ethanoic acid, we have 2 intramolecular hydrogen bonds. For water we have 2 intermolecular hydrogen bonds, therefore, the strongest interaction will be in the ethanoic acid.

The closer boiling point to the 75ºC is the ethanol (boiling point of 78.8 ºC) therefore these molecules would have enough energy to break the hydrogen bonds and to past from liquid to gas.

4 0

3 years ago

the chemical compound C2F4 is used to make PTEE (Teflon). How manyC2F4 molecules are in 485 kilograms of this material?

monitta

Answer:

$molecules=2.92x10^{27}moleculesC_2F_4$

Explanation:

Hello,

In this case, we use the Avogadro's number to compute the molecules of C2F4 whose molar mass is 100 g/mol contained in a 485-kg sample as shown below:

$molecules=485kgC_2F_4*\frac{1000gC_2F_4}{1kgC_2F_4} *\frac{1molC_2F_4}{100gC_2F_4}*\frac{6.022x10^{23}molecules C_2F_4}{1molC_2F_4} \\\\molecules=2.92x10^{27}moleculesC_2F_4$

Best regards,

5 0

3 years ago

How to write generic word equation and a chemical equation for the reaction that occurs when an anhydrous salt is placed in wate

Oksana_A [137]

The generic solution of the reaction that occurs would be writen as water + anhydrous salt = hydrated salt
chemical equation would look like this xH2O +AB = AB.xH2O

3 0

3 years ago

You find the user guide for your DVD player. Which is the best section to start looking for information about a problem? glossar

melomori [17]

Troubleshooting is the correct answer I believe

5 0

3 years ago

Read 2 more answers

In the titration of 50. 0 mL of 0. 400 M HCOOH with 0. 150 M LiOH, how many mL of LiOH are required to reach the equivalence poi

mart [117]

The volume of the 0.15 M LiOH solution required to react with 50 mL of 0.4 M HCOOH to the equivalence point is 133.3 mL

<h3>Balanced equation </h3>

HCOOH + LiOH —> HCOOLi + H₂O

From the balanced equation above,

The mole ratio of the acid, HCOOH (nA) = 1

The mole ratio of the base, LiOH (nB) = 1

<h3>How to determine the volume of LiOH </h3>

Molarity of acid, HCOOH (Ma) = 0.4 M
Volume of acid, HCOOH (Va) = 50 mL
Molarity of base, LiOH (Mb) = 0.15 M

Volume of base, LiOH (Vb) =?

MaVa / MbVb = nA / nB

(0.4 × 50) / (0.15 × Vb) = 1

20 / (0.15 × Vb) = 1

Cross multiply

0.15 × Vb = 20

Divide both side by 0.15

Vb = 20 / 0.15

Vb = 133.3 mL

Thus, the volume of the LiOH solution needed is 133.3 mL

Learn more about titration:

brainly.com/question/14356286

8 0

2 years ago