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guapka [62]
4 years ago
9

What is the density of a rectangular block that has a mass of 500 grams and a volume of 50cm^3

Chemistry
1 answer:
oee [108]4 years ago
6 0
Density = mass / volume

D = 500 g / 50 cm³

D = 10 g/cm³

hope this helps!
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The thiocyanate polyatomic ion, SCN-, is commanly called a pseudohalogen because it acts very much like halide ions. For example
harina [27]

Answer:

A) \frac{1mol(SCN)_{2}}{2molNaSCN}

B) 0.025 mol (SCN)₂

C) 2 mol (SCN)₂

D) \frac{1molMnSO_{4}}{2molH_{2}SO_{4}}

E) 3.5504 mol H₂SO₄

Explanation:

2NaSCN +2H₂SO₄ + MnO₂ → (SCN)₂ + 2H₂O + MnSO₄ + Na₂SO₄

A) A conversion factor could be \frac{1mol(SCN)_{2}}{2molNaSCN} , as it has the units that we want to <u>convert to in the numerator</u>, and the units that we want to <u>convert from in the denominator</u>.

B) 0.05 mol NaSCN *  \frac{1mol(SCN)_{2}}{2molNaSCN} = 0.025 mol (SCN)₂

C) With 4 moles of NaSCN and 3 moles of MnSO₄, the<em> reactant </em>is NaSCN so we use that value to calculate the moles of product formed:

4 mol NaSCN * \frac{1mol(SCN)_{2}}{2molNaSCN} = 2 mol (SCN)₂

D) \frac{1molMnSO_{4}}{2molH_{2}SO_{4}}

E) 1.7752 mol MnSO₄ * \frac{2molH_{2}SO_{4}}{1molMnSO_{4}} = 3.5504 mol H₂SO₄

5 0
3 years ago
In a reaction between vinegar and antacid tablets, the antacid is the limiting reagent. At constant pressure and temperature, th
lyudmila [28]

1200cm³ of gas

Explanation:

From the analogy provided in this problem,

we know that;

     three tablets will produce 600cm³ of gas

 This implies that;

    1 tablet of the antacid will produce \frac{600}{3} = 200cm³

 If 1 tablet of the antacid produces 200cm³ of gas,

under the same condition;

  6 tablets will produce = 6 x 200 = 1200cm³ of gas

learn more:

Boyle's law brainly.com/question/8928288

#learnwithBrainly

4 0
3 years ago
Use your knowledge of valence electrons and how they affect bonds to figure out how carbon (Group 14) and oxygen (Group 16)
kenny6666 [7]

Answer: D

Explanation:

O=C=O

5 0
3 years ago
Is length an extensive or intensive physical property?
kati45 [8]

Answer:

The answer to your question is length is an extensive property

Explanation:

There are two physical properties: extensive and intensive properties.

An extensive property is a property that depends on the amount of matter.

An intensive property is a property that does not depend on the amount of matter.

7 0
3 years ago
PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEWSE HELP PLEASE H
marishachu [46]

Answer:

23.6 moles

Explanation:

From the question given above, the following data were obtained:

Mass of air = 3.6 Kg

Mass percentage of O₂ = 21%

Number of mole of O₂ =?

Next, we shall convert 3.6 Kg of air to grams (g). This can be obtained as follow:

1 kg = 1000 g

Therefore,

3.6 Kg = 3.6 Kg × 1000 / 1 kg

3.6 Kg = 3600 g

Next, we shall determine the mass of O₂ in the air. This can be obtained as follow:

Mass of air = 3600 g

Mass percentage of O₂ = 21%

Mass of O₂ =?

Mass of O₂ = 21% × 3600

Mass of O₂ = 21/100 × 3600

Mass of O₂ = 756 g

Finally, we shall determine the number of mole of O₂ in the sample of air. This can be obtained as follow:

Mass of O₂ = 756 g

Molar mass of O₂ = 2 × 16 = 32 g/mol

Number of mole of O₂ =?

Mole = mass /Molar mass

Number of mole of O₂ = 756 / 32

Number of mole of O₂ = 23.6 moles

Thus, the number of mole of O₂ in the

sample of air is 23.6 moles

7 0
3 years ago
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