What is one of the most common ways workers get hurt around machines

Ductility (increases/decreases/does not change) with temperature.

PSYCHO15rus [73]

Answer:

Increases

Explanation:

Ductility:

Ductility is the property of material to go permanent deformation due to tensile load.In other words the ability of material to deform in wire by the help of tensile load.

When temperature is increase then ductility will also increases.And when temperature decreases then the ductility will also decreases.As we know that at very low temperature material become brittle and this is know as ductile brittle transition.

8 0

3 years ago

What is a table saw for

svet-max [94.6K]

Answer:

a table

Explanation:

because you can saw the table

5 0

2 years ago

Read 2 more answers

Water flows in a constant diameter pipe with the following conditions measured:

Burka [1]

Answer:

a) $h_L=-3.331ft$

b) The flow would be going from section (b) to section (a)

Explanation:

1) Notation

$p_a =31.1psi=4478.4\frac{lb}{ft^2}$

$p_b =27.3psi=3931.2\frac{lb}{ft^2}$

For above conversions we use the conversion factor $1psi=144\frac{lb}{ft^2}$

$z_a =56.7ft$

$z_a =68.8ft$

$h_L =?$ head loss from section

2) Formulas and definitions

For this case we can apply the Bernoulli equation between the sections given (a) and (b). Is important to remember that this equation allows en energy balance since represent the sum of all the energies in a fluid, and this sum need to be constant at any point selected.

The formula is given by:

$\frac{p_a}{\gamma}+\frac{V_a^2}{2g}+z_a =\frac{p_b}{\gamma}+\frac{V_b^2}{2g}+z_b +h_L$

Since we have a constant section on the piple we have the same area and flow, then the velocities at point (a) and (b) would be the same, and we have just this expression:

$\frac{p_a}{\gamma}+z_a =\frac{p_b}{\gamma}+z_b +h_L$

3)Part a

And on this case we have all the values in order to replace and solve for $h_L$

$\frac{4478.4\frac{lb}{ft^2}}{62.4\frac{lb}{ft^3}}+56.7ft=\frac{3931.2\frac{lb}{ft^2}}{62.4\frac{lb}{ft^3}}+68.8ft +h_L$

$h_L=(71.769+56.7-63-68.8)ft=-3.331ft$

4)Part b

Analyzing the value obtained for $\h_L$ is a negative value, so on this case this means that the flow would be going from section (b) to section (a).

5 0

3 years ago

Explain why it is important to understand hydrostatic forces on surfaces when designing scuba gear, particularly oxygen tanks, f

Andrei [34K]

Answer:

Explained

Explanation:

Oxygen tank = Oxygen enriched air tank

Hydro static pressure increases with the depth, generally around 1 bar for 10 meters of depth. This high pressure condition leads to increasing in the partial pressure of oxygen in the scuba tank. This leads to a condition called oxygen toxicity. It causes when breathing molecular oxygen at higher partial pressures. It leads to cell damage in the nervous system, lungs, and eyes. So, while designing such gear we have to be careful that oxygen partial pressure shouldn't exceed certain pressure.

3 0

3 years ago

The net negative charge flowing through a device varies as q(t) = 2.2 t2 C. Find the current through the device at t = 0, 0.5, a

Leni [432]

Answer:

The current at t= 0 sec, is 0 A

The current at t= 0.5 sec, is 2.2 A

The current at t= 1 sec, is 4.4 A

Explanation:

Given that

q(t) = 2.2 t²

We know that:- the change in the charge w.r.t. time is known as current. So,

$I=\dfrac{dq}{dt}$

q(t) = 2.2 t²

$\dfrac{dq}{dt}= 4.4 t$

I= 4.4 t

1.

t = 0 s :

I = 4.4 x 0 = 0 A

Therefore, the current at t= 0 sec, is 0 A

2 .

t= 0.5 s :

I = 4.4 x 0.5 = 2.2 A

Therefore, the current at t= 0.5 sec, is 2.2 A

3.

t= 1 s

I = 4.4 x 1 =4.4 A

Therefore, the current at t= 1 sec, is 4.4 A

4 0

3 years ago