The height at which the mass will be lifted is; 3 meters
<h3>How to utilize efficiency of a machine?</h3>
Formula for efficiency is;
η = useful output energy/input energy
We are given
η = 60% = 0.6
Input energy = 4 KJ = 4000 J
Thus;
0.6 = useful output energy/4000
useful output energy = 0.6 * 4000
useful output energy = 2400 J
Work done in lifting mass(useful output energy) = force * distance moved
Useful output energy = 800 * h
where h is height to lift mass
Thus;
800h = 2400
h = 2400/800
h = 3 meters
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Answer:
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Answer:
vacancy formation energy of Ni is 1.400 eV
Explanation:
given data
number of vacancies in Ni = 4.7 x
atomic weight = 58.69 g/mol
density = 8.8 g/cm³
solution
we get here N that is
N =
...........1
N = 
N =
and here no of vacancy will be
Nv =
.................2
put here value

take ln both side
Qv = 1.400 eV
so vacancy formation energy of Ni is 1.400 eV
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Explanation: