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MrRa [10]
3 years ago
11

Their game off badminton is always on Tuesday

Engineering
1 answer:
igomit [66]3 years ago
5 0

Ok? is this a question or what?

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Air at 300 K and 100 kPa steadily flows into a hair dryer having electrical work input of 1500 W. Because of the size of the air
dezoksy [38]

Answer:

0.0280Kg/s

Explanation:

Given:

W = 1500

V2 = 300

V1 = 0

Q = 0 ( adiabatic)

T1 = 300

T2 = 20 m/s = converting to degrees we have 353°c

Let's use the energy equation

Q - W = m_• *( Cp(dT) + 0.5*(V2^2 - V1^2) Q = 0

[/tex] m_• = W / (Cp(dT) + 0.5*V2^2) [/tex]

= 1500 / (1005(353 - 300) + 0.5*21^2)

= 1500 W / 53485.5 =0.0280 kg/s

8 0
4 years ago
Read 2 more answers
Coulomb's Law Two point charges experience an attractive force of 10.8 N when they are separated by 2.4 m. VWhat force in newton
SashulF [63]

Answer:

The force between the charges when the separation decreases to 0.7 meters equals 126.955 Newtons

Explanation:

We know that for two point charges of magnitude q_{1},q_{2} the magnitude of force between them is given by

F=\frac{k_{e}q_{1}\cdot q_{2}}{r^{2}}

where

k_{e} is constant

r is the separation between the charges

Initially when the charges are separated by 2.4 meters the force can be calculated as

F_{1}=\frac{k_{e}\cdot q_{1}q_{2}}{2.4^{2}}\\\\10.8=\frac{k_{e}\cdot q_{1}q_{2}}{2.4^{2}}\\\\\therefore k_{e}\cdot q_{1}q_{2}=10.8\times 2.4^{2}=62.208

Now when the separation is reduced to 0.7 meters the force is similarly calculated as

F_{2}=\frac{k_{e}\cdot q_{1}q_{2}}{0.7^{2}}

Applying value of the constant we get

F_{1}=\frac{62.208}{0.7^{2}}

Thus F_{2}=126.955Newtons

5 0
3 years ago
Technician a s ays a shorted circuit can generate excessive heat. technician b says a shorted circuit will cause the circuit pro
Lerok [7]

Based on the information provided, the technician who is correct is: C. Both Technician A and Technician B.

<h3>What is an open circuit?</h3>

An open circuit can be defined as a type of electric circuit in which the continuity between the conducting wire (paths) has been broken or cut.

This ultimately implies that, an open circuit is designed and developed to prevent the flow of electric charges (electrons or currents) from one point in an electric circuit to another.

In Electrical engineering, a short usually causes an electric circuit protection device such as a fuse, circuit breaker, etc., to open when higher than normal current flows through the electrical circuit.

Read more on short circuit here: brainly.com/question/25018411

#SPJ1

Complete Question:

Technician A says a shorted circuit can generate excessive heat. Technician B says a shorted circuit will cause the circuit protection device to open. who is correct?

A. Technician A only

B. Technician B only

C. Both Technician A and B

D. Neither Technician A nor B

5 0
1 year ago
. A two-dimensional fluid motion is represented by a point vortex of strength Γ set at distance c from an infinite straight soli
Lostsunrise [7]

Answer:

The solution and complete explanation for the above question and mentioned conditions is given below in the attached document.i hope my explanation will help you in understanding this particular question.

Explanation:

8 0
3 years ago
A single-phase 50-kVA, 2400/240-volt, 60-Hz distribution transformer is used as a step-down transformer at the load end of a 240
Marrrta [24]
Who yuh think ago read di wull a that guh sleep it’s C tho
8 0
3 years ago
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