<h3>
Answer:</h3>
Ba(NO₃)₂(aq) + CuSO₄(aq) ⟶ BaSO₄(s) + CU(NO₃)₂(aq)
2K₃PO₄(aq) + 3MgCl₂(aq) ⟶ 6KCl(aq) + Mg₃(PO₄)₂(s)
<h3>
Explanation:</h3>
- Precipitation reactions are types of reactions that involve a reaction between soluble salts to form an insoluble salt or a precipitate and a soluble salt.
- The equations given in the question are examples of precipitation reactions that lead to the formation of precipitates BaSO₄ and Mg₃(PO₄)₂
- The balanced equations are;
Ba(NO₃)₂(aq) + CuSO₄(aq) ⟶ BaSO₄(s) + CU(NO₃)₂(aq)
2K₃PO₄(aq) + 3MgCl₂(aq) ⟶ 6KCl(aq) + Mg₃(PO₄)₂(s)
- Based on solubility rules, all sulfates are soluble except CaSO₄, BaSO₄, PbSO₄ and silver sulfate. Therefore, BaSO₄ is a precipitate and will have a solid-state.
- All phosphates are insoluble except those of ammonium, potassium, and sodium. Therefore, Mg₃(PO₄)₂ is a precipitate and will have a soluble state.
Answer:
The initial volume of the chlorine gas
Explanation:
Given:
P1= 686mmHg
P2= 991mmHg
V2= 5076mL
V1=?
According to Boyle's law which states that at a constant temperature, the pressure on a gas increases as it's volume decreases.
It can be expressed as : P1V1 = P2V2
Where P1 is the initial pressure
P2= final pressure
V1= initial volume
V2 = final volume
V1= (991mmHg*507.6mL)/686mmHg
V1=503031.6/686
Therefore, The initial volume of the chlorine gas
Answer:
0.322630 mols
Explanation:
You have to divide the given by the molar mass then multiply by the mol ratio which in this case is 1:1
B is the correct answer i believe