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Aliun [14]
3 years ago
11

Two competing models attempt to explain the motions and changing brightness of the planets: Ptolemy's geocentric model and Coper

nicus' heliocentric model.
Sort the characteristics according to whether they are part of the geocentric model, the heliocentric model, or both solar system models.

Drag the appropriate items to their respective bins.

Epicycles and deferents help explain planetary motion.
Planets move in circular orbits and with uniform motion.
The brightness of a planet increases when the planet is closest to Earth.
This model is Earth-centered.
This model is Sun-centered.
Retrograde motion is explained by the orbital speeds of planets.
Retrograde motion is explained by epicycles.
Epicycles and deferents help explain planetary motion. Selected

Dragable

Geocentric:

Heliocentric:

Both geocentric and heliocentric:
Physics
1 answer:
Ivanshal [37]3 years ago
6 0

Geocentric:

-The model is Earth centered

-Retrograde motion is explained by epicycles.

Heliocentric:

-This model is Sun-centered.

-Retrograde motion is explained by the orbital speeds of planets.

Both geocentric and heliocentric:

-Epicycles and deferents help explain planetary motion.

-Planets move in circular orbits and with uniform motion.

-The brightness of a planet increases when the planet is closest to Earth.

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Which physical change in which gas directly to a solid is​
Misha Larkins [42]

Answer:deposition

Explanation:reeeeeeeee

5 0
3 years ago
One boat tows another boat by means of a tow line, which is under a constant tension of 465 N. The boats move at a constant spee
Ludmilka [50]

Answer:

Work done, W = 141174 Joules

Explanation:

It is given that,

Constant tension acting on the boat, T = F = 465 N

Speed of the boat, v = 4.6 m/s

Time, t = 1.1 min = 66 seconds

Let W is the work done by the tension. It is equal to the product of force and displacement. It is given by :

W=F\times d

Since, d=vt

W=F\times v\times t

W=465\ N\times 4.6\ m/s\times 66\ s

W = 141174 Joules

So, the work is done by the tension is 141174 Joules. Hence, this is the required solution.

6 0
3 years ago
If light of wavelength 700 nm strikes such a photocathode, what will be the maximum kinetic energy, in eV , of the emitted elect
Oksana_A [137]

If the light of wavelength 700 nm strikes such a photocathode the maximum kinetic energy, in eV, of the emitted electrons is 0.558 eV.

so - $KE_{max} = hc/lembda}  work

threshold when KE = 0

hc/lambda = work = 1240/900=1.38 eV

b) Kemax = hc/lambda - work = 1240/640 -1.38=0.558 eV

What is photocathode?

  • A photocathode electrolyte interface can be used in a photoelectrolysis cell as the primary light-harvesting junction (in conjunction with an appropriate electrochemical anode) or as an optically complementary photoactive half-cell in a tandem photoelectrode photoelectrolysis cell (Hamnett, 1982; Kocha et al, 1994).
  • In the case of the former, the electrode should ideally harvest photon energy across the majority of the solar spectrum in order to achieve the highest energy conversion efficiency possible.
  • In the latter case, however, the photocathode may only be active in a specific band of the solar spectrum in order to generate a cathodic photocurrent sufficient to match the current generated in the photoanodic half-cell.

To learn more about Photocathode from the given link:

brainly.com/question/9861585

#SPJ4

3 0
2 years ago
Two 2.0-cm-diameter insulating spheres have a 6.60 cm space between them. One sphere is charged to + 76.0 nC , the other to - 30
e-lub [12.9K]

Answer:

5.2\times 10^5N/C

Explanation:

Since the two charged bodies are symmetric, we can calculate the electric field taking both of them as point charges.

This can be easily seen if we use Gauss's law, \int{E} \, dA=\frac{Q_{enclosed}}{\epsilon_o}

We take a larger sphere of radius, say r, as the Gaussian surface. Then the electric field due to the charged sphere at a distance r from it's center is given by,

E=\frac{1}{4\pi r^2} \frac{Q_{enclosed}}{\epsilon_o}

which is the same as that of a point charge.

In our problem the charges being of opposite signs, the electric field will add up. Therefore,

E_{total}=\frac{1}{4\pi\epsilon_o}\frac{q_1+q_2}{r^2}= (9\times10^9) \frac{(76+30)\times10^{-9}}{((1+3.3)\times10^{-2})^2}N/C =5.2\times10^5N/C

where, r = distance between the center of one sphere to the midpoint (between the 2 spheres)

8 0
3 years ago
PLEASE HELP THIS IS URGENT!!!!! 50 POINTS!!!
Alja [10]
What math class are you in I think I can help
6 0
3 years ago
Read 2 more answers
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