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algol [13]
3 years ago
9

PLEASE HELP!! Salmon often jump waterfalls to reach their

Physics
1 answer:
AlexFokin [52]3 years ago
8 0

Answer:

7.13781 m/s

Explanation:

X-direction             | Y-direction

x=v_{xo}t+\frac{1}{2}a_{x}t^2      | y=v_{yo}t+\frac{1}{2}a_{y}t^2

3.41=v_{o}cos(28.4)t  | 0.397=v_{yo}sin(28.4)t+\frac{1}{2} (-9.81)t^2

3.41=v_{o}(0.87964)t  | 0.397=v_{yo}sin(28.4)(\frac{3.87658}{v_{o} })+\frac{1}{2} (-9.81)(\frac{3.87658}{v_{o} })^2

\frac{3.41}{0.87964}=v_{o}t             | 0.397=1.84379-\frac{73.71171}{v^2}

\frac{3.87658}{v_{o} } =t                | 7.13781=v

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Answer:

Following are the solution to this question:

Explanation:

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3 years ago
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Answer:

the answer is B

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4 0
2 years ago
How much work does it take to lift 345 boxes to a height of 6.00 m of each box has a mass of 7.89 kg
Art [367]

Given the value of the mass of each boxes, the work done in lifting the boxes to the given height is 1.6 × 10⁵J.

<h3>Work done</h3>

Work done is simply defined as the energy transfer that takes place when an object is either pushed or pulled over a certain distance by an external force. It is expressed as;

W = F × d

Where F is force applied or Weight and d is distance

Also Force = Weight = mass × acceleration due to gravity.

Since gravity is acting on the boxes as it been lift

W = Weight × height from ground level

W = mg × d

Where m is mass of the boxes, g is accelration due to gravity( g = 9.8m/s² ) and d is distance from ground level.

Given the data in the question;

  • Since each box has a mass of 7.89 kg
  • Mass of the 345 boxes = 345 × 7.89 kg = 2722.05kg
  • Distance or height d = 6.0m
  • Work done W = ?

To determine the work done, we substitute our values into the expression above.

W = mg × d

W = 2722.05kg × 9.8m/s² × 6.0m

W = 160056.5kgm²/s²

W = 160056.5J

W = 1.6 × 10⁵J

Therefore,  Given the value of the mass of each boxes, the work done in lifting the boxes to the given height is 1.6 × 10⁵J.

Learn more about work done here: brainly.com/question/26115962

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2 years ago
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Answer:

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5min × 60sec

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600÷300

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