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algol [13]
3 years ago
9

PLEASE HELP!! Salmon often jump waterfalls to reach their

Physics
1 answer:
AlexFokin [52]3 years ago
8 0

Answer:

7.13781 m/s

Explanation:

X-direction             | Y-direction

x=v_{xo}t+\frac{1}{2}a_{x}t^2      | y=v_{yo}t+\frac{1}{2}a_{y}t^2

3.41=v_{o}cos(28.4)t  | 0.397=v_{yo}sin(28.4)t+\frac{1}{2} (-9.81)t^2

3.41=v_{o}(0.87964)t  | 0.397=v_{yo}sin(28.4)(\frac{3.87658}{v_{o} })+\frac{1}{2} (-9.81)(\frac{3.87658}{v_{o} })^2

\frac{3.41}{0.87964}=v_{o}t             | 0.397=1.84379-\frac{73.71171}{v^2}

\frac{3.87658}{v_{o} } =t                | 7.13781=v

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Why do telescopes give modern astronomers an advantage over people in the past
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In a given chemical reaction the energy of the products is less than the energy of the reactants which statement is true for thi
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Group of answer choices.

A. Energy is absorbed in the reaction.

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C. There is no transfer of energy in the reaction.

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B. Energy is released in the reaction.

Explanation:

A chemical reaction can be defined as a chemical process which typically involves the transformation or rearrangement of the atomic, ionic or molecular structure of an element through the breakdown and formation of chemical bonds to produce a new compound or substance.

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II. Exothermic reaction: it's a chemical reaction in which heat is liberated into the environment.

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Calculate the force of gravity between planet X and planet y if both planets are 3.75 X 10^11 m apart, planet X has a mass of 1.
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So, the force of gravity that the asteroid and the planet have on each other approximately \boxed{\sf{2.9 \times 10^{17} \: N}}

<h3>Introduction</h3>

Hi ! Now, I will help to discuss about the gravitational force between two objects. The force of gravity is not affected by the radius of an object, but radius between two object. Moreover, if the object is a planet, the radius of the planet is only to calculate the "gravitational acceleration" on the planet itself,does not determine the gravitational force between the two planets. For the gravitational force between two objects, it can be calculated using the following formula :

\boxed{\sf{\bold{F = G \times \frac{m_1 \times m_2}{r^2}}}}

With the following condition :

  • F = gravitational force (N)
  • G = gravity constant ≈ \sf{6.67 \times 10^{-11}} N.m²/kg²
  • \sf{m_1} = mass of the first object (kg)
  • \sf{m_2} = mass of the second object (kg)
  • r = distance between two objects (m)

<h3>Problem Solving</h3>

We know that :

  • G = gravity constant ≈ \sf{6.67 \times 10^{-11}} N.m²/kg²
  • \sf{m_X} = mass of the planet X = \sf{1.55 \times 10^{22}} kg.
  • \sf{m_Y} = mass of the planet Y = \sf{3.95 \times 10^{28}} kg.
  • r = distance between two objects = \sf{3.75 \times 10^{11}} m.

What was asked :

  • F = gravitational force = ... N

Step by step :

\sf{F = G \times \frac{m_X \times m_Y}{r^2}}

\sf{F = 6.67 \cdot 10^{-11} \times \frac{1.55 \cdot 10^{22} \cdot 3.95 \times 10^{28}}{(3.75 \times 10^{11})^2}}

\sf{F \approx \frac{40.84 \times 10^{-11 + 22 + 28}}{14.0625 \times 10^{22}}}

\sf{F \approx 2.9 \times 10^{39 - 22}}

\sf{F \approx 2.9 \times 10^{17} \: N}

<h3>Conclusion</h3>

So, the force of gravity that the asteroid and the planet have on each other approximately

\boxed{\sf{2.9 \times 10^{17} \: N}}

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