Answer:
is their a picture or something
Explanation:
Answer:
15 V
Explanation:
Electric potential is given as the product of Electric field and distance. Mathematically:
V = E * r
Where E = Electric field
r = distance = 6m
Electric field, E, is:
E = F / q
Where F = Electric force = 5N
q = Electric charge = 2C
Therefore, electric potential will be:
V = (F * r) / q
V = (5 * 6) / 2
V = 15V
Incomplete question as many data is missing.I have assumed value of charge and electric field.The complete question is here
A charge of 28 nC is placed in a uniform electric field that is directed vertically upward and that has a magnitude of 5.00×10⁴ V/m.
What work is done by the electric force when the charge moves a distance of 2.70 m at an angle of 45.0 degrees downward from the horizontal?
Answer:

Explanation:
Given data
Charge q=28 nC
Electric field E=5.00×10⁴ V/m.
Distance d=2.70 m
Angle α=45°
To find
Work done by electric force
Solution

Answer:
Catch these points g thanks
Explanation:
0.1
Amount of matter in object is mass.density is mass/volume.h2o is water.drew first picture of atom is Neil's Bohr.l* w* h is volume.basic unit of matter is atom.mixture is concrete.n=1 is inner shell.upward force of a liquid on an object is buoyancy.