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Monica [59]
3 years ago
5

A baseball rolls off of a 0.70 m high desk at 0.66m/s.How far from the base of the desk will it hit the floor?

Physics
1 answer:
sergij07 [2.7K]3 years ago
5 0
0.66 m/s is the answer to this question final answer
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Please help it’s urgent
Sidana [21]

Answer:

I believe it's sound energy.

Explanation:

Sound can move through air, whereas electric and radiant energy don't have to.

6 0
3 years ago
Give reason Pascal is a derived unit​
Stells [14]

Answer:

Pascal is a derived unit because <u>it</u><u> </u><u>cannot</u><u> </u><u>be</u><u> </u><u>expressed</u><u> </u><u>in</u><u> </u><u>any</u><u> </u><u>physics</u><u> </u><u>terms</u><u>,</u><u> </u><u>but</u><u> </u><u>it</u><u> </u><u>is</u><u> </u><u>an</u><u> </u><u>expression</u><u> </u><u>of</u><u> </u><u>fundamental</u><u> </u><u>quantities</u><u>.</u>

Explanation:

{ \sf{Pasacal \: ( Pa) =  \frac{newtons}{metres {}^{2} } }} \\  \\ { \sf{Pasacal  \: (Pa) =  \frac{kg \times  {ms}^{ - 2} }{ {m}^{2} } }}

4 0
3 years ago
A starship blasts past the earth at 2.0*10^8 m/s .Just after passing the earth, the starship fires a laser beam out its back of
Vilka [71]

Answer:

at the speed of light (c=3.0\cdot 10^8 m/s)

Explanation:

The second postulate of the theory of the special relativity from Einstein states that:

"The speed of light in free space has the same value c in all inertial frames of reference, where c=3.0\cdot 10^8 m/s"

This means that it doesn't matter if the observer is moving or not relative to the source of ligth: he will always observe light moving at the same speed, c.

In this problem, we have a starship emitting a laser beam (which is an electromagnetic wave, so it travels at the speed of light). The startship is moving relative to the Earth with a speed of 2.0*10^8 m/s: however, this is irrelevant for the exercise, because according to the postulate we mentioned above, an observer on Earth will observe the laser beam approaching Earth with a speed of c=3.0\cdot 10^8 m/s.

7 0
3 years ago
A Boeing 747 "Jumbo Jet" has a length of 59.7 m. The runway on which the plane lands intersects another runway. The width of the
tia_tia [17]

Answer:

t = 1.48 s

Explanation:

As we know that length of the Boeing plane is

L = 59.7 m

width of the intersection is given as

w = 25.0 m

now we know that deceleration of the plane is given as

a = -5.4 m/s^2

Also the final speed of the plane while it clears the intersection is given as

v_f = 53 m/s

now we have

d = (\frac{v_f + v_i}{2}) t

(25 + 59.7) = (\frac{53 + v_i}{2}) t

also we know that

v_f - v_i = at

53 - v_i = -5.4 t

now we have

84.7 = (\frac{53 + 53 + 5.4t}{2})t

by solving above equation we have

t = 1.48 s

5 0
3 years ago
Pls help
goldenfox [79]

Chemical Energy                                                                  

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3 0
3 years ago
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