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gulaghasi [49]
3 years ago
9

Where are the nucleus and the electrons located in this atom

Physics
1 answer:
levacccp [35]3 years ago
5 0
In the middle the nucleus is thr brain of it and the electrons spin around the whole atom
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To show the electron configuration for an atom, when would it be better to use an orbital notation than to use a written configu
lakkis [162]

when the aim is to show electron distributions in shells.

hope this helps :)

5 0
4 years ago
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When one person was talking in a small room, the sound intensity level was 60 dB everywhere within the room. Then, there were 14
dolphi86 [110]

Answer:

E= 71dB

Explanation:

See attached file for step by step calculation

3 0
3 years ago
A car, moving along a straight stretch of highway,
yarga [219]
<span>We know that an object in moving with acceleration follow the rule according that the distance covered will be : d = Vi*t + 1/2*a*t^2 where d is distance, Vi is initial speed, and a is acceleration Then after 1 km which is 1000 metres we have: 1000 = Vi *71.2 + 1/2*0.0499*(71.2)^2 Vi = (1000-1/2*0.0499*(71.2)^2)/71.2 = 1000/71.2 - 1/2*0.0499*71.2 = 12.27 m/s Then the car was going at 12.27 m/s when started to accelerate.</span>
5 0
4 years ago
A syringe containing 1.55 ml of oxygen gas is cooled from 95.3 °c to 0.0 °c. what is the final volume of oxygen gas?\
irinina [24]
Consider the gas to be an ideal gas (it will obey all the introductory gas laws). Also you have to note that the gas will not change phase. It won't.

T_s (Temperature Start) = 95.3o C = 95.3 + 273 = 368.3 oK (degrees Kelvin)
T_e (Temperature End) = 0o C + 273 = 273 oK

Initial volume = Vi = 1.55 mL (no need to change to Liters. The answer will be in mL

 Vi /Ts =  Ve / Vs Ve is the unknown volume that you seek.
1.55 / 368.3  =  Ve / 273
Ve = 1.55 * 273 / 368.3
Ve = 1.1489 mL

If your teacher is concerned about Sig digs, then 0.0 has only two.
Your answer should be 1.1 mL, but I'll give you the choice.



3 0
4 years ago
Estimate the acceleration due to gravity at the surface of Europa (one of the moons of Jupiter) given that its mass is 4.9×1022k
Taya2010 [7]

Answer:g=1.97 m/s^2

Explanation:

Given

mass of Jupiter is M=4.9\times 10^{22} kg

Density of Jupiter is same as Earth

density\ of\ Earth=density\ of\ Jupiter=5510 kg/m^3

mass=volume\times density

considering Jupiter to be sphere of radius r

M=\frac{4}{3}\times \pi r^3\times \rho

r^3=\frac{3M}{\rho \times 4\pi}

r^3=\frac{3\times 4.9\times 10^{22}}{5510\times 4\pi}

r=(\frac{3\times 4.9\times 10^{22}}{5510\times 4\pi})^{\frac{1}{3}}

r=1.28\times 10^6 m

acceleration due to gravity is given by

g=\frac{GM}{r^2}

g=\frac{6.67\times 10^{-11}\times 4.9\times 10^{22}}{(1.28\times 10^6)^2}

g=1.97 m/s^2

3 0
4 years ago
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