Question

If you had excess chlorine, how many moles of of aluminum chloride could be produced from 25.0 g of aluminum? Express your answer to three significant figures and include the appropriate units. View Available Hint(s) nothing nothing Part B If you had excess aluminum, how many moles of aluminum chloride could be produced from 30.0 g of chlorine gas, Cl2? Express your answer to three significant figures and include the appropriate units.

Answer 1

Answer:

A. From 25,0 g of aluminium you will produce 0,927 moles of aluminium chloride

B. From 30,0 g of chlorine gas you will produce: 0,282 moles of aluminium chloride

Explanation:

a. The reaction that you have in this problem is:

3 Cl₂ + 2 Al → 2 AlCl₃

25,0 g of aluminium are:

25,0 ₓ$\frac{1mole}{26,98g}$ = 0,927 moles

As Al:AlCl₃ ratio is 1, from 25,0 g of aluminium you will produce: 0,927 moles of aluminium chloride

b. 30,0 g of chlorine gas are:

30,0 ₓ$\frac{1mole}{70,90g}$ = 0,423 moles of Cl₂

As Cl₂:AlCl₃ ratio is ³/₂:

0,423 moles of Cl₂ ₓ $\frac{2 molesAlCl_3}{3 molesCl_2}$ = 0,282 moles of aluminium chloride

Thus, from 30,0 g of chlorine gas you will produce: 0,282 moles of aluminium chloride

I hope it helps!