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2 years ago

Which of these atoms has the largest number of neutrons in the nucleus?

Chemistry

1 answer:

viktelen [127]2 years ago

8 0

Holonium and Gadolinium has the highest number of neutrons in the nucleus.

Looking at the atoms listed;

Dysprosium has 66 protons

Holonium has 67 protons

Neodymium has 60 protons

Europium has 63 protons

Gadolinium has 64 protons

Then,

Number of neutrons = Mass number - number of protons

For Dysprosium

157 - 66 = 91 neutrons

For Holonium

162 - 67 = 95 neutrons

For Neodymium

149 - 60 = 89 neutrons

For Europium

148 - 63 = 85 neutrons

For Gadolinium

159 - 64 = 95 neutrons

Hence, Holonium and Gadolinium has the highest number of neutrons in the nucleus.

Learn more: brainly.com/question/14156701

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A sample of ammonia ^NH3h gas is completely decomposed to nitrogen and hydrogen gases over heated iron wool. If the total pressu

icang [17]

Answer : The partial pressure of $N_2$ and $H_2$ is, 216.5 mmHg and 649.5 mmHg

Explanation :

According to the Dalton's Law, the partial pressure exerted by component 'i' in a gas mixture is equal to the product of the mole fraction of the component and the total pressure.

Formula used :

$p_i=X_i\times p_T$

$X_i=\frac{n_i}{n_T}$

So,

$p_i=\frac{n_i}{n_T}\times p_T$

where,

$p_i$ = partial pressure of gas

$X_i$ = mole fraction of gas

$p_T$ = total pressure of gas

$n_i$ = moles of gas

$n_T$ = total moles of gas

The balanced decomposition of ammonia reaction will be:

$2NH_3\rightarrow N_2+3H_2$

Now we have to determine the partial pressure of $N_2$ and $H_2$

$p_{N_2}=\frac{n_{N_2}}{n_T}\times p_T$

Given:

$n_{N_2}=1\\\\n_{H_2}=3\\\\n_{T}=4\\\\p_T=866mmHg$

$p_{N_2}=\frac{1}{4}\times (866mmHg)=216.5mmHg$

and,

$p_{H_2}=\frac{n_{H_2}}{n_T}\times p_T$

Given:

$n_{H_2}=1\\\\n_{H_2}=3\\\\n_{T}=4\\\\p_T=866mmHg$

$p_{H_2}=\frac{3}{4}\times (866mmHg)=649.5mmHg$

Thus, the partial pressure of $N_2$ and $H_2$ is, 216.5 mmHg and 649.5 mmHg

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3 years ago

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