Titration is a common method of determining the amount or concentration of an unknown substance. The method is easy to use if the quantitative relationship between two reacting solutions is known. The method is particularly well-suited to acid-base and oxidation-reduction reactions. Titrations are routinely used in industry to analyze products to be sold. Many manufacturers are under strict standards of quality control because their products are sold for public consumption. In this experiment, we will analyze a number of commercial products and, in some cases, test the validity of the information given on their labels and/or the claims made in television commercials. The products to be tested include antacid tablets, vinegar, fruit juice, and household ammonia.
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Consider the amount of energy needed to brake the bonds.
In c=o there are both a pi-bond and a sigma bond. Therefore it requires a higher energy to brake it. When considering the c-o bond there is only a single sigma bond is needed to be broken. Therefore braking is easier.
When something is easily broken they are having a weak attraction. When they harder to break they are having a stronger attraction.
Here weak attraction is having a lower energy while stronger attraction has higher energy.
Therefore c=o provides a high energy than c-o
The exception to the rule concerning the solubility of chlorides in water is PbCl2.
The solubility rules give us an idea of which substances are soluble in water and what substances are not soluble in water. According to the solubility rules, chlorides are soluble in water.
However, chlorides of lead are not soluble in water hence, the exception to the rule is PbCl2.
Learn more: brainly.com/question/6505878
Answer:
a) 2.29E4
Explanation: 1kg = 1000g. to get mass in grams multiply 22.9 kg by 1000g then divide by 1 kg to cancel the kg.
b) 2,29E5 g
c) 2.29 E10 μg
Answer:
- Partial pressure He = 276 torr
- Partial pressure Ar = 457 torr
- Total pressure = 733 torr
Explanation:
Assuming temperature remains constant, we can use Boyle's law to solve this problem: P₁V₁=P₂V₂.
Once the two flasks are connected and the stopock opened, the total volume is:
Now we use Boyle's law <em>twice</em>, to <u>calculate the new pressure of </u><em><u>each</u></em><u> gas</u>:
- He ⇒ 752 torr * 275 mL = P₂He * 750 mL
P₂He = 276 torr
- Ar ⇒ 722 torr * 475 mL = P₂Ar * 750 mL
P₂Ar = 457 torr
Finally we <u>calculate the total pressure</u>, adding the partial pressures:
- Total pressure = P₂He + P₂Ar = 733 torr
