Answer:
The final velocity of the runner at the end of the given time is 2.7 m/s.
Explanation:
Given;
initial velocity of the runner, u = 1.1 m/s
constant acceleration, a = 0.8 m/s²
time of motion, t = 2.0 s
The velocity of the runner at the end of the given time is calculate as;
where;
v is the final velocity of the runner at the end of the given time;
v = 1.1 + (0.8)(2)
v = 2.7 m/s
Therefore, the final velocity of the runner at the end of the given time is 2.7 m/s.
Answer:
(1) V=0.03348 gallons
(2) L= 576.813 km .
Explanation:
Write the relation between the density and volume for ethanol.
density ( ρ )= m/V
Volume ( V )= m/ρ .......... (1)
Here, V is the volume of ethanol, m is the mass of ethanol, and is the density of ethanol.
Write the relation between the specific gravity of ethanol and density of water
ρ=γ*ρ(water) ............. (2)
Here, is specific gravity of ethanol and is the density of water.
Determine the volume of ethanol by substituting equation (2) in equation (1)
V=m/γ*ρ(water)
Substitute 100 gm , for m, for , and 1000 kg/m for.
V=
V=0.000112674
Convert m³ to gallons
V= (0.000112674*264.172 )
V=0.03348 gallons
Step 2:
Determine the distance travelled by the special vehicle named “Micro joule” runs with ethanol.
L=C*V .......... (3)
Here, is the rate of consumption of ethanol by Micro joule.
Substitute 10,705 mi/gallons for C and 0.03348 gallons for .
By using eq. 3.
L= 10750*0.03348
L=358.416 mi.
Convert the distance travelled by Micro joule from miles to kilometres
L= (358.416* 1.60934)
L = 576.813 km
Thus, the distance travelled by Micro joule is 576.813 km .