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3 years ago

Listening to the radio, you can hear two stations at once. Describe this wave interaction

2 answers:

8 0

Actually says Pantazis, since their frequencies are so wildly different, brain waves don’t interfere with radio waves. Even if that was the case, brain waves are so weak, they are hardly measurable at all. For comparison, says Pantazis, “the magnetic field of the earth is just strong enough to move the needle of a compass. Signals from the brain are a billionth of that strength.”

777dan777 [17]3 years ago

6 0

the answer is interference

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Which use of iron is due to its chemical properties?

AfilCa [17]

Colored sparks and rusting.

3 0

2 years ago

The diameter of Earth (to two significant figures) is 7900 miles. Calculate its circumference.

Bess [88]

Answer:

The circumference of the Earth is 24818.58 miles

Explanation:

Analysis conceptual : The formula of the circumference is the following:

L= π*D Formula (1)

Where:

L : is the length of the circumference in miles (mi)

π : is the constant

D : is the diameter of the circumference in miles (mi)

Known data

π = 3.1416

D= 7900 miles: Diameter of the Earth

Problem development

We apply the formula 1 to calculate the circumference of the Earth (L):

L= π*7900 miles

L= 24818.58 miles

8 0

3 years ago

A 25-kg child sits at the top of a 4-meter slide. After sliding down, the child is traveling at 5 m/s. How much PE does he start

Semmy [17]

Daniddmelo says it right there, don't know why he got reported.

The potential energy (PE) is mass x height x gravity. So it would be 25 kg x 4 m x 9.8 = 980 joules. The child starts out with 980 joules of potential energy. The kinetic energy (KE) is (1/2) x mass x velocity squared. KE = (1/2) x 25 kg x 5 m/s2 = 312.5 joules. So he ends with 312.5 joules of kinetic energy. The Energy lost to friction = PE - KE. 980- 312.5 = 667.5 joules of energy lost to friction.

Please don't just copy and paste, and thank you Dan cause you practically did it I just... elaborated more? I dunno.

4 0

3 years ago

A 120 g, 8.0-cm-diameter gyroscope is spun at 1000 rpm and allowed to precess. What is the precession period?

dolphi86 [110]

To solve this problem we will derive the expression of the precession period from the moment of inertia of the given object. We will convert the units that are not in SI, and finally we will find the precession period with the variables found. Let's start defining the moment of inertia.

$I = MR^2$

Here,

M = Mass

R = Radius of the hoop

The precession frequency is given as

$\Omega = \frac{Mgd}{I\omega}$

Here,

M = Mass

g= Acceleration due to gravity

d = Distance of center of mass from pivot

I = Moment of inertia

$\omega$ = Angular velocity

Replacing the value for moment of inertia

$\Omega= \frac{MgR}{MR^2 \omega}$

$\Omega = \frac{g}{R\omega}$

The value for our angular velocity is not in SI, then

$\omega = 1000rpm (\frac{2\pi rad}{1 rev})(\frac{1min}{60s})$

$\omega = 104.7rad/s$

Replacing our values we have that

$\Omega = \frac{9.8m/s^2}{(8*10^{-2}m)(104.7rad)}$

$\Omega = 1.17rad/s$

The precession frequency is

$\Omega = \frac{2\pi rad}{T}$

$T = \frac{2\pi rad}{\Omega}$

$T = \frac{2\pi}{1.17}$

$T = 5.4 s$

Therefore the precession period is 5.4s

7 0

2 years ago

In the diagram shown, satellite S moves in a circular orbit around the Earth (E) in a counterclockwise direction.

zubka84 [21]

The characteristics of the velocity vector used to find the results for the direction of acceleration and velocity are:

Acceleration is towards the center of the circle

The velocity is tangent to the circle counterclockwise.

Newton's Second Law establishes a relationship between force, mass and acceleration of bodies.

<h3>Centripetal acceleration. </h3>

In the case of circular motion there is a constant change in the direction of the velocity vector, even when its module remains constant, this change in direction points towards the center of the circle, so that the module is constant.

They indicate that the satellite is moving counterclockwise, therefore the speed must go to the left (counterclockwise) tangential to the circle.

In conclusion using the characteristics of the velocity vector we can find the results for the direction of acceleration and velocity are:

Acceleration is towards the center of the circle

The velocity is tangent to the circle counterclockwise.

Learn more about centripetal acceleration here: brainly.com/question/25243603

6 0

2 years ago