Layer F was formed earlier than Layer A
V^2-u^2=2as
v=final velocity=unkown
u=initial velocity=0 m/s, because freely falling
a=acceleration due to gravity=9.8 m/s^2
s=distance (here height) traveled=4.5m
therefore the final velocity,
v^2=2*9.8*4.5
v=<span>9.39m/s</span>
Answer:
So the repulsive force between the pith ball will be 
Explanation:
We have given that the pith ball have the equal charge q = -40 nC =
Distance between the charges = 10 cm =0.1 m
According to coulombs law 

So the repulsive force between the pith ball will be 
Answer:
-47.04
Explanation:
Divide 12 m by 2.5 m/s which equals 4.8s
And then use 4.8s to multiply it with -9.8
4.8(-9.8)= -47.04 m/s
Hope this helped!! :)