A small 12.00 g plastic ball is suspended by a string in a uniform, horizontal electric field. If the ball is in equilibrium whe
n the string makes a 30 angle with the vertical, what is the net charge on the ball
1 answer:
Answer: Here is the complete question:
A small 12.00g plastic ball is suspended by a string in a uniform, horizontal electric field with a magnitude of 103 N/C. If the ball is in equilibrium when the string makes a 30 angle with the vertical, what is the net charge on the ball?
Answer: The charge on the ball is 5.71 × 10^-4 C
Explanation:
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Answer:
73.52983 Hp
Explanation:
m = Mass of car =
W = Weight of car = 12000 N
a = Acceleration = 0.96 m/s²
Velocity of the car
From the question
Balancing the forces
The power is 73.52983 Hp
Answer:
(a) 4.75 m/s² (b) 7.6 N
Explanation:
Given that,
The mass of a lab cart, m = 1.6 kg
Initial speed, u = 0.5 m/s
Final speed, v = 4.3 m/s
Time, t = 0.8 s
(a) The acceleration of an object is equal to the rate of change of velocity. It can be calculated as :
(b) Let F be the net force on the cart. It can be given by :
F = ma
Hence, this is the required solution.