Two positive charges of 20 micro coulomb and 100 micro coulomb and the distance between them is 150cm.What will be the electrica
1 answer:
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Explanation:
First we will convert the given mass from lb to kg as follows.
157 lb =
= 71.215 kg
Now, mass of caffeine required for a person of that mass at the LD50 is as follows.
= 12818.7 mg
Convert the % of (w/w) into % (w/v) as follows.
0.65% (w/w) =
=
=
Therefore, calculate the volume which contains the amount of caffeine as follows.
12818.7 mg = 12.8187 g =
= 1972 ml
Thus, we can conclude that 1972 ml of the drink would be required to reach an LD50 of 180 mg/kg body mass if the person weighed 157 lb.
Answer:
1.44 x 10⁻⁶ C
Explanation:
= charge on one sphere
= charge on other sphere
= Total charge on the two spheres = 40 μC
=
= 40 x 10⁻⁶
= (40 x 10⁻⁶) -
eq-1
= distance between the two spheres = 50 cm = 0.50 m
= magnitude of force between the two spheres = 2.0 N
Magnitude of force between the two spheres is given as
= 1.44 x 10⁻⁶ C