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Blababa [14]
3 years ago
6

Potential energy is _____ energy. A. heat B. stored C. released

Physics
2 answers:
Triss [41]3 years ago
8 0

Answer:

B. stored

Explanation:

crimeas [40]3 years ago
3 0

Answer:

Potential energy is stored energy.

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A battery-operated car moves forward as a result of which device? Electromagnet, generator, motor, or a transformer?
Romashka [77]

A battery-operated car moves forward as a result of which device?

A) Electromagnet

B) Generator

<u>C) Motor </u>

D) Transformer

7 0
3 years ago
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Which of the following is a good conductor of heat? 1. water 2. glass 3. wood 4. mercury​
trapecia [35]

Answer:

So the answer would be water based on the evidence shown below.

Explanation:

Mercury is a poor conductor of heat but good for electricity, water is a good conductor of heat but a poor conductor of electricity, wood is a poor conductor of heat and electricity, and glass is probably the worst conductor of heat.

7 0
3 years ago
Figure 1 shows the motion of three balls. The curved paths followed by balls B and Care examples of
nlexa [21]

Answer:

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7 0
3 years ago
What is the wavelength of a wave that has a speed of 160 m/s and a period of 3.7 ms?
Elza [17]

Answer:

160m/s

Explanation:

The speed of a wave is related to its frequency and wavelength, according to this equation:

v=f ×λ

3 0
2 years ago
A copper rod of cross-sectional area 11.6 cm2 has one end immersed in boiling water and the other in an ice-water mixture, which
julia-pushkina [17]

Answer:

0.686 g of ice melts each second.

Solution:

As per the question:

Cross-sectional Area of the Copper Rod, A = 11.6\ cm^{2} = 11.6\times 10^{- 4}\ m^{2}

Length of the rod, L = 19.6 cm = 0.196 m

Thermal conductivity of Copper, K = 390\ W/m.^{\circ}C

Conduction of heat from the rod per second is given by:

q = \frac{KA\Delta T}{L}

where

\Delta T = 100^{\circ} - 0^{\circ} = 100^{\circ}C = temperature difference between the two ends of the rod.

Thus

q = \frac{390\times 11.6\times 10^{- 4}\times 100}{0.196} = 228.48\ J/s

Now,

To calculate the mass, M of the ice melted per sec:

M = \frac{q}{L_{w}}

where

L_{w} = Latent heat of fusion of water = 333 kJ/kg

M = \frac{228.48}{333\times 10^{3}} = 6.86\times 10^{- 4}\ kg = 0.686\ g

5 0
3 years ago
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