Question

Calcium chromate, cacro4, has a ksp of 7.1×10−4. what happens when calcium and chromate solutions are mixed to give 0.0200 m ca2+ and 0.0300 m cro42−

Answer 1

The solubility equilibrium of $CaCrO_{4}$:

[tex] CaCrO_{4}(aq)<===>Ca^{2+}(aq) + CrO_{4}^{2-}(aq)\\
Q_{sp}=[Ca^{2+}][CrO_{4}^{2-}]\\
= (0.0200 M)(0.0300 M) \\
= 0.0006

Ksp (0.00071) > Qsp (0.0006). So, no precipitate would form.