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Goshia [24]
3 years ago
15

Give the mass percent of hydrogen in c14h19no2.

Chemistry
2 answers:
stiv31 [10]3 years ago
6 0
Mass Percent of Hydrogen is 8.2085%
Zolol [24]3 years ago
4 0

Answer: 8.1 %

Explanation:

Molecular mass of C_{14}H_{19}NO_2  =  235 g/mol

Atomic mass of hydrogen atom = 1 g/mol

Percentage of an element in a compound:

\frac{\text{Number of atoms of element}\times \text{Atomic mass of element}}{\text{molecular mass of element}}\times 100

Mass Percentage of hydrogen:

\frac{19\times 1g/mol}{235 g/mol}\times 100=8.1\%

The mass percent of hydrogen in C_{14}H_{19}NO_2 is 8.1%.

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Katarina [22]

Answer:

empirical formula: H_2SO_4

2 g H

32.7 g S

65.3 g O

Explanation:

Like the problem said, the first thing we can do is calculate the mass of each of the 3 elements in a 100-gram sample:

- 2.00% * 100g = 2 g H

- 32.7% * 100g = 32.7 g S

- 65.3% * 100g = 65.3 g O

Now we need to find the empirical formula from these. To do so, convert all of those masses into moles by using the molar mass for each element:

- the molar mass of H is 1.01 g/mol

- the molar mass of S is 32.06 g/mol

- the molar mass of O is 16 g/mol

2 g H ÷ 1.01 g/mol = 1.98 mol H

32.7 g S ÷ 32.06 g/mol = 1.02 mol S

65.3 g O ÷ 16 g/mol = 4.08 mol O

Our ratio of H : S : O is now:

1.98 mol : 1.02 mol : 4.08 mol

Divide them all by the smallest number, which is 1.02:

1.98/1.02  :  1.02/1.02  :  4.08/1.02

1.94 : 1 : 4

1.94 ≈ 2

So:

2 : 1 : 4

Thus, the empirical formula is: H_2SO_4.

7 0
3 years ago
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