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Strike441 [17]
3 years ago
14

What are 2 facts about Lysosome

Chemistry
1 answer:
Aleonysh [2.5K]3 years ago
6 0
<span><span>The Lysosome organelles <span> have several dozen of enzymes in each one.</span>
</span><span> The word "Lysosome" comes from two Greek words. One, "Lysis" meaning destruction and two, "Soma" meaning body
</span><span>There is really no way for a lysosome organelle to malfunction execpt if the cell starts eating to much and there are not enough lysosomes to digest all of the food. Which leeds up to the cell not being able to eat anymore.</span></span>
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State the number of neutrons in an atom of Ne-20 and the number of neutrons in an atom of Ne-22. choose two answers * 1 point Ne
saveliy_v [14]

Answer:

Ne 20: 10

and

Ne 22: 12

Explanation:

Ne-20:

N = A - Z = 20 - 10 = 10 neutrons

Ne-22:

N = A - Z = 22 - 10 = 12 neutrons

N: number of neutrons

A: mass number

Z: atomic number

8 0
3 years ago
The maximum level of lead allowed in drinking water is 15 mg/kg. What is this concentration in units of parts per million?
Alecsey [184]
15 ppm
1.5 × 10-2 ppm
1.5 × 104 ppm
3.1 ppm
1.5 × 10-2 ppm
6 0
3 years ago
All invertebrates are part of the same phylum A) True B) False PLZZZ HELP
amm1812

hello, the answer to your question would be TRUE!

(this is because a phylum is "a principal taxonomic category that ranks above class and below kingdom.")

<em> i hope this helps, and have a great day. :)</em>

8 0
4 years ago
Read 2 more answers
A 25.00 mL sample of of a sulfurous acid solution is completely neutralized using 17.12 mL of 0.13 M sodium hydroxide. What is t
Kryger [21]

Answer:

0.0445 M is the initial concentration of sulfurous acid.

Explanation:

H_2SO_3+2NaOH\rightarrow Na_2SO_3+2H_2O

To calculate the concentration of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is H_2SO_3

are the n-factor, molarity and volume of base which is NaOH.

We are given:

n_1=2\\M_1=?\\V_1=25.00mL\\n_2=1\\M_2=0.13 M\\V_2=17.12 mL

Putting values in above equation, we get:

2\times M_1\times 25.00 mL=1\times 0.13 M\times 17.12 mL

x=\frac{1\times 0.13 M\times 17.12 mL}{2\times 25.00}=0.0445 M

0.0445 M is the initial concentration of sulfurous acid.

8 0
3 years ago
A sample of 0.600 mol of a metal m reacts completely with excess fluorine to form 46.8 g of mf2. how many moles of f are in the
oksian1 [2.3K]
The balanced chemical reaction is expressed as:

M + F2 = MF2

To determine the moles of the element fluorine present in the product, we need to determine the moles of the product formed from the reaction and relate this value to the ratio of the elements in MF2. We do as follows:

moles MF2 produced = 0.600 mol M ( 1 mol MF2 / 1 mol M ) = 0.600 mol MF2
molar mass MF2 = 46.8 g MF2 / 0.6 mol MF2 = 78 g/mol
moles MF2 = 46.8 g ( 1 mol / 78 g ) = 0.6 mol
moles F = 0.6 mol MF2 ( 2 mol F / 1 mol MF2 ) = 1.2 moles F
6 0
3 years ago
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