Answer:
Similarly, the distance between two points P1 = (x1,y1,z1) and P2 = (x2,y2,z2) in xyz-space is given by the following generalization of the distance formula, d(P1,P2) = (x2 x1)2 + (y2 y1)2 + (z2 z1)2. This can be proved by repeated application of the Pythagorean Theorem.
Step-by-step explanation:
Use a calculator
Answer:
They would meet each other at
PM.
Step-by-step explanation:
- Erik took a trip to see his friend Mike who lives 308 miles away.
- He left his place at 10 AM driving at 70 mph.
- In 2 hours, his friend Mike left his place driving towards Erik at an average speed of 50 mph.
As Erik left his house at 10 AM driving at 70 mph and in 2 hours, his friend Mike left his place driving towards Erik at an average speed of 50 mph. It means
Erik left his place at 12:00 PM noon.
so, at 12:00 PM Erik had already traveled:

Miles left 
Let 't' be the time when they meet
so





so
or
hour and
minutes after
noon
i.e.

Therefore, they would meet each other at
PM.
Answer:
The answer is (1,2) I'm pretty sure that is the answer if it is not please tell me I'll check.