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Zinaida [17]
3 years ago
7

Part of the basic procedures is the vehicle check. What does that mean?

Engineering
1 answer:
saul85 [17]3 years ago
5 0

The choices are:

a. bringing it to a mechanic for a tune-up

b. checking to make sure it is in working order

c. making sure you are entering your vehicle

d. giving the tires a good kick to check traction

Answer:

The answer is: letter b, checking to make sure it is in working order.

Explanation:

A "vehicle check" is essential for everyone involved. It makes the driver and the passengers safe, and also extends that safety to the people in the environment. Before driving, you need to check your car for the following: <em>fluids, wipers, spare wheels, leaks and the like</em>. This will ensure that your vehicle is in proper working order and <u>will lessen the possibility of car accident in the future.</u>

Thus, this explains the answer, letter b.

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The self weight of dam.

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In a tensile test on a steel specimen, true strain = 0.12 at a stress of 250 MPa. When true stress = 350 MPa, true strain = 0.26
scZoUnD [109]

Answer:

The strength coefficient is 625 and the strain-hardening exponent is 0.435

Explanation:

Given the true strain is 0.12 at 250 MPa stress.

Also, at 350 MPa the strain is 0.26.

We need to find  (K) and the (n).

\sigma =K\epsilon^n

We will plug the values in the formula.

250=K\times (0.12)^n\\350=K\times (0.26)^n

We will solve these equation.

K=\frac{250}{(0.12)^n} plug this value in 350=K\times (0.26)^n

350=\frac{250}{(0.12)^n}\times (0.26)^n\\ \\\frac{350}{250}=\frac{(0.26)^n}{(0.12)^n}\\  \\1.4=(2.17)^n

Taking a natural log both sides we get.

ln(1.4)=ln(2.17)^n\\ln(1.4)=n\times ln(2.17)\\n=\frac{ln(1.4)}{ln(2.17)}\\ n=0.435

Now, we will find value of K

K=\frac{250}{(0.12)^n}

K=\frac{250}{(0.12)^{0.435}}\\ \\K=\frac{250}{0.40}\\\\K=625

So, the strength coefficient is 625 and the strain-hardening exponent is 0.435.

5 0
3 years ago
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