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Olenka [21]
2 years ago
12

Ruler game, HELPPPPP

Engineering
2 answers:
geniusboy [140]2 years ago
8 0
The answer would be D as the arrow is pointing halfway between 2 and 3 making it 2 and a half
viktelen [127]2 years ago
3 0
D! :D
Hope I helped!!
You might be interested in
Tensile testing provides engineers with the ability to verify and establish material properties related to a specific material.
Sedbober [7]

Answer:

True

Explanation:

Tensile testing which is also referred to as tension testing is a process which materials are subjected to so as to know how well it can be stretched before it reaches breaking point. Hence, the statement in the question is true

7 0
2 years ago
Information such as tolerances and scale can be found in the _______________ of an engineering drawing.
nasty-shy [4]

Answer:

Information such as tolerance and scale can be found in the <u>title block</u> of an engineering drawing

Explanation:

The title block of an engineering drawing can normally be found on the lower right and corner of an engineering drawing and it carries the information that are used to specify details that are specific the drawing including, the name of the project, the name of the designer, the name of the client, the sheet number, the drawing tolerance, the scale, the issue date, and other relevant information, required to link the drawing with the actual structure or item

8 0
2 years ago
Evaluate the performance of the proposed heat pump for three locations Using R134a. Discuss the effect of outdoor temperature on
Phoenix [80]

Answer:Table 2.2: Differences in runstitching times (standard − ergonomic).

1.03 -.04 .26 .30 -.97 .04 -.57 1.75 .01 .42

.45 -.80 .39 .25 .18 .95 -.18 .71 .42 .43

-.48 -1.08 -.57 1.10 .27 -.45 .62 .21 -.21 .82

A paired t-test is the standard procedure for testing this null hypothesis.

We use a paired t-test because each worker was measured twice, once for Paired t-test for

each workplace, so the observations on the two workplaces are dependent. paired data

Fast workers are probably fast for both workplaces, and slow workers are

slow for both. Thus what we do is compute the difference (standard − er-

gonomic) for each worker, and test the null hypothesis that the average of

these differences is zero using a one sample t-test on the differences.

Table 2.2 gives the differences between standard and ergonomic times.

Recall the setup for a one sample t-test. Let d1, d2, . . ., dn be the n differ-

ences in the sample. We assume that these differences are independent sam-

ples from a normal distribution with mean µ and variance σ

2

, both unknown.

Our null hypothesis is that the mean µ equals prespecified value µ0 = 0

(H0 : µ = µ0 = 0), and our alternative is H1 : µ > 0 because we expect the

workers to be faster in the ergonomic workplace.

The formula for a one sample t-test is

t =

¯d − µ0

s/√

n

,

where ¯d is the mean of the data (here the differences d1, d2, . . ., dn), n is the The paired t-test

sample size, and s is the sample standard deviation (of the differences)

s =

vuut

1

n − 1

Xn

i=1

(di − ¯d )

2 .

If our null hypothesis is correct and our assumptions are true, then the t-

statistic follows a t-distribution with n − 1 degrees of freedom.

The p-value for a test is the probability, assuming that the null hypothesis

is true, of observing a test statistic as extreme or more extreme than the one The p-value

we did observe. “Extreme” means away from the the null hypothesis towards

the alternative hypothesis. Our alternative here is that the true average is

larger than the null hypothesis value, so larger values of the test statistic are

extreme. Thus the p-value is the area under the t-curve with n − 1 degrees of

freedom from the observed t-value to the right. (If the alternative had been

µ < µ0, then the p-value is the area under the curve to the left of our test

Explanation: The curve represents the sum total of the evaluation

4 0
3 years ago
Power cords can be damaged by Which of the following?
Elena L [17]
What are the options??
3 0
2 years ago
The following information pertains to the January operating budget for Casey Corporation. ∙ Budgeted sales for January $200,000
stich3 [128]

Answer:

For January, budgeted cost of goods sold is $150,000

Explanation:

Sales is the consists of Gross income and Cost of goods sold. We can derive the gross income value after deducting cost of goods sold from sales value.

Budgeted Sales for next month = $200,000

Gross Margin = 25%

Gross Margin = Gross Income / Sales

25% = Gross Income / $200,000

Gross Income is the net value of sales and cost of goods sold.

Gross Income = $200,000 x 25%

Gross Income = $50,000

As we know,

Gross Income = Sales - Cost of Goods sold

$50,000 = $200,000 - Cost of Goods sold

Cost of Goods sold = $200,000 - $50,000

Cost of Goods sold = $150,000

5 0
3 years ago
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